Which of the following reactions will result in 2,2-dibromopropane? (a) \(\mathrm{CH}_{3} \mathrm{C} \equiv \mathrm{CH}+2 \mathrm{HBr} \rightarrow\) (b) \(\mathrm{CH}_{3}-\mathrm{CBr}=\mathrm{CH}_{2}+\mathrm{HBr} \rightarrow\) (c) \(\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}_{2}+\mathrm{Br}_{2} \rightarrow\) (d) \(\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CHBr}+\mathrm{HBr} \rightarrow\)

Short Answer

Expert verified
Reactions (b) and (c) will result in the production of 2,2-dibromopropane.

Step by step solution

01

(Reaction (a))

We have \(\mathrm{CH}_{3} \mathrm{C} \equiv \mathrm{CH}+2 \mathrm{HBr} \rightarrow\). This reaction involves the addition of HBr to an alkyne. When two HBr molecules react with an alkyne, we get a dibrominated alkane. In this case, the dibrominated product will be: \(\mathrm{CH}_{3}\mathrm{C}(\mathrm{Br})_{2}\mathrm{CH}_{2}\mathrm{Br}\), which is not 2,2-dibromopropane.
02

(Reaction (b))

We have \(\mathrm{CH}_{3}-\mathrm{CBr}=\mathrm{CH}_{2}+\mathrm{HBr} \rightarrow\). This reaction involves the addition of HBr to an alkene with an existing bromine atom. The hydrogen will be added to the carbon with the least number of hydrogen atoms, and the bromine will be added to the other carbon, resulting in: \(\mathrm{CH}_{3}\mathrm{CHBr}\mathrm{CH}_{2}\mathrm{Br}\), which is 2,2-dibromopropane.
03

(Reaction (c))

We have \(\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}_{2}+\mathrm{Br}_{2} \rightarrow\). This reaction involves the addition of Br2 to an alkene. The two bromine atoms will be added in an anti-addition across the double bond, resulting in: \(\mathrm{CH}_{3}\mathrm{CHBr}\mathrm{CH}_{2}\mathrm{Br}\), which is also 2,2-dibromopropane.
04

(Reaction (d))

We have \(\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CHBr}+\mathrm{HBr} \rightarrow\). This reaction involves the addition of HBr to an alkene with an existing bromine atom. The hydrogen will be added to the least number of hydrogen atoms, and the bromine will be added to the other carbon, resulting in: \(\mathrm{CH}_{3}\mathrm{CH}(\mathrm{Br})_{2}\mathrm{CH}_{2}\mathrm{H}\), which is not 2,2-dibromopropane. From our analysis, we can deduce that reactions (b) and (c) will result in the production of 2,2-dibromopropane.

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