Which of the following compounds can exhibit geometrical isomerism? (a) \(\mathrm{IBrC}=\mathrm{CFCI}\) (b) Cinnamic acid (c) Benzophenone oxime (d)

Short Answer

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Answer: (a) \(\mathrm{IBrC}=\mathrm{CFCI}\) and (b) Cinnamic acid can exhibit geometrical isomerism.

Step by step solution

01

Identify the structure of each compound

We will first identify the structure of each given compound: (a) \(\mathrm{IBrC}=\mathrm{CFCI}\) : this structure contains a carbon-carbon double bond between two carbon atoms, each of which has two different halogens attached to it. (b) Cinnamic acid: the structure of cinnamic acid is \(\mathrm{C_6H_5CH=CHCOOH}\), which has a carbon-carbon double bond with a phenyl group and an acidic group attached to it. (c) Benzophenone oxime: the structure of benzophenone oxime is \(\mathrm{C_{6}H_{5}C=NOH}\), which contains a carbon-nitrogen double bond with a phenyl group, an oxygen atom, and a hydrogen atom. (d) 1, 3-dibromopropane: The structure of 1, 3-dibromopropane is \(\mathrm{CH_2BrCH_2CH_2Br}\), which has no double bonds or special cyclic structures.
02

Determine the possibility for geometrical isomerism in each compound

Next, let's determine if these compounds can exhibit geometrical isomerism based on their structures: (a) \(\mathrm{IBrC}=\mathrm{CFCI}\): This compound has a carbon-carbon double bond, and each carbon has two different halogens attached to it. Therefore, this compound can exhibit geometrical isomerism in the form of cis-trans isomers. (b) Cinnamic acid: This compound has a carbon-carbon double bond, with a phenyl group and an acidic group attached to it. The double bond can allow for geometrical isomerism in the form of cis-trans isomers. (c) Benzophenone oxime: Although it has a carbon-nitrogen double bond, it cannot exhibit geometrical isomerism due to the similar groups attached to the nitrogen atom (oxygen and hydrogen). (d) 1, 3-dibromopropane: This compound does not have any double bonds or special cyclic structures that would permit geometrical isomerism. Therefore, it cannot exhibit geometrical isomerism.
03

Conclusion

From the given options, (a) \(\mathrm{IBrC}=\mathrm{CFCI}\) and (b) Cinnamic acid can exhibit geometrical isomerism. The other two compounds, (c) Benzophenone oxime and (d) 1, 3-dibromopropane, cannot exhibit geometrical isomerism due to their structures.

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