Match the elements of Column I to elements of Column II. There can be single or multiple matches. Column I (a) Neopentane (b) Cyclohexane (c) 2,2 -dimethyl butane (d) \(2,2,3,3-\) tetramethyl butane Column II (p) equatorial hydrogens (q) Secondary hydrogens (r) Quaternary carbon (s) Only one monochloro derivative

Draw the structural formulas of the compounds in Column I as follows: (a) Neopentane (b) Cyclohexane (c) 2,2-dimethyl butane (d) 2,2,3,3-tetramethyl butane

Look for the features mentioned in Column II: (p) equatorial hydrogens (q) Secondary hydrogens (r) Quaternary carbon (s) Only one monochloro derivative

Now, let's proceed to match the elements from both the columns. (a) Neopentane Neopentane has a quaternary carbon and it forms only one monochloro derivative. Thus, it matches with (r) and (s). (b) Cyclohexane Cyclohexane has equatorial hydrogens in its chair conformation as well as secondary hydrogens. Thus, it matches with (p) and (q). (c) 2,2-dimethyl butane 2,2-dimethyl butane also has secondary hydrogens. Thus, it matches (q). (d) \(2,2,3,3-\) tetramethyl butane 2,2,3,3-tetramethyl butane has quaternary carbon. Thus, it matches (r). So, the matches are as follows: Column I - Column II (a) Neopentane - (r) Quaternary carbon & (s) Only one monochloro derivative (b) Cyclohexane - (p) equatorial hydrogens & (q) Secondary hydrogens (c) 2,2-dimethyl butane - (q) Secondary hydrogens (d) \(2,2,3,3-\) tetramethyl butane - (r) Quaternary carbon