Four reagents and specific reactions in which they are involved are given. Identify the wrongly matched option among the following (a) Hot alcoholic KOH \(-\) dehydrohalogenation (b) \(\mathrm{H}^{+} / \mathrm{H}_{2} \mathrm{O}\) - hydration (c) \(\mathrm{H}^{+} / \Delta\) - dehydration (d) Unsymmetrical alkene - anti Markovnikov addition

Short Answer

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(a) Hot alcoholic KOH - dehydrohalogenation (b) H+ / H2O - hydration (c) H+ / Δ - dehydration (d) Unsymmetrical alkene - anti Markovnikov addition Answer: (d) Unsymmetrical alkene - anti Markovnikov addition

Step by step solution

01

Understand each reagent's role in the specified reaction

First, let's recall what each of the reagents does in their respective reactions: (a) Hot alcoholic KOH is a strong base that usually causes dehydrohalogenation in some organic compounds. (b) Adding a positive hydrogen ion, \(\mathrm{H}^{+}\), in the presence of water, \(\mathrm{H}_{2}\mathrm{O}\) usually results in hydration - the addition of water across the double or triple bond. (c) A positive hydrogen ion, \(\mathrm{H}^{+}\), with the application of heat, is usually used for dehydration - the removal of water from the organic compound. (d) Unsymmetrical alkene refers to the presence of an alkene (double bond), with different groups attached to the bonded carbon atoms. Anti-Markovnikov addition refers to the addition of a nucleophile in a manner opposite to the Markovnikov's rule.
02

Identify the wrongly matched option

Now, the task is to identify the wrongly matched option from the given list. Let's go through each option: (a) Hot alcoholic KOH \(-\) dehydrohalogenation is a well-known reaction, so this option is correct. (b) \(\mathrm{H}^{+} / \mathrm{H}_{2} \mathrm{O}\) - hydration is also correct, as adding \(\mathrm{H}^{+}\) in the presence of water generally results in hydration. (c) \(\mathrm{H}^{+} / \Delta\) - dehydration is also correct since applying heat with the presence of \(\mathrm{H}^{+}\) causes dehydration. Now let's look at option (d). Unsymmetrical alkene is a type of alkene with a double bond, and anti-Markovnikov addition is a way certain reactions add to this double bond. However, this option is not describing any specific reaction or reagent. It's simply describing a type of substrate and a manner of attack, so it's not a matched pair like the other options. So our solution is:
03

Answer

The wrongly matched option among the given ones is (d) Unsymmetrical alkene - anti Markovnikov addition.

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