Chapter 2: Problem 54
When \(\mathrm{n}\) -hexane is passed over heated alumina or chromic oxide catalyst under pressure, the product formed is (a) Iso hexane (b) cyclohexane (c) butane and ethane (d) Benzene
Chapter 2: Problem 54
When \(\mathrm{n}\) -hexane is passed over heated alumina or chromic oxide catalyst under pressure, the product formed is (a) Iso hexane (b) cyclohexane (c) butane and ethane (d) Benzene
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Get started for freeWhen 3-methyl-2-butanol reacts with HBr, the expected product is 2-bromo-3-methyl-butane. But the actual product formed is 2 -bromo-2-methylbutane. Account for this.
Simplest alkane which can exhibit optical activity is (a) 3 -methyl hexane (b) 3 -methyl heptane (c) 2 -methyl butane (d) neopentane
Question contains Statement-1 and Statement-2 and has the following choices (a), (b), (c) and (d), out of which ONLY ONE is correct. (a) Statement- 1 is True, Statement- 2 is True; Statement- 2 is a correct explanation for Statement-1 (b) Statement- 1 is True, Statement- 2 is True; Statement- 2 is NOT a correct explanation for Statement-1 (c) Statement- 1 is True, Statement- 2 is False (d) Statement-1 is False, Statement- 2 is True Statement 1 \(\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{3}\) is more reactive towards \(\mathrm{HBr}\) compared to ethylene. and Statement 2 The carbocation formed in \(\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{3}\) during the addition of \(\mathrm{HBr}\) is more stabilized compared to the cation formed from ethylene.
This section contains multiple choice questions. Each question has 4 choices (a), (b), (c) and (d), out of which ONLY ONE is correct. A compound with the molecular formula, \(\mathrm{C}_{4} \mathrm{H}_{6}\), does not exist in cis or trans form. It does not produce a precipitate with ammoniacal \(\mathrm{AgNO}_{3}\) solution. The compound as such is optically inactive but a monohalogen derivative can be optically active. The compound is (a) \(\mathrm{CH}_{3} \mathrm{C} \equiv \mathrm{C}-\mathrm{CH}_{3}\) (b) \(\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{C}=\mathrm{CH}_{2}\) (c) \(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{C} \equiv \mathrm{C}-\mathrm{H}\) (d)
Directions: Each question contains Statement-1 and Statement-2 and has the following choices (a), (b), (c) and (d), out of which ONLY ONE is correct. (a) Statement- 1 is True, Statement- 2 is True; Statement- 2 is a correct explanation for Statement-1 (b) Statement- 1 is True, Statement- 2 is True; Statement- 2 is NOT a correct explanation for Statement-1 (c) Statement-1 is True, Statement- 2 is False (d) Statement- 1 is False, Statement- 2 is True Statement 1 Erythro-2,3-dibromobutane on reaction with zinc and alcohol gives trans 2 -butene. and Statement 2 Elimination requires trans periplanar geometry.
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