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Chapter 2: Problem 66

Identify the product in the given reaction. \(\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CH}_{2}+\mathrm{NOCl} \rightarrow(\mathrm{A})\) (a) \(\mathrm{CH}_{3}-\mathrm{CHCl}-\mathrm{CH}_{2} \mathrm{NO}\) (b) (c) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHClNO}\) (d) \(\mathrm{CH}_{3} \mathrm{NOCH}_{2} \mathrm{CH}_{2} \mathrm{Cl}\)

Short Answer

Expert verified
Answer: The product of the reaction is CH3CH2CHClNO.

Step by step solution

01

Determine the reaction type

Since the reactants include an alkene and a molecule with a halogen (Cl), we can conclude that this is an addition reaction. In an addition reaction, the double bond of the alkene reacts with a molecule to form two new single bonds. Thus, the product will have a single bond between the two carbon atoms instead of the double bond in the alkene \(\mathrm{CH}_{3}\mathrm{CH}=\mathrm{CH}_{2}\).
02

Determine the outcome of the addition reaction

The reaction between the alkene and NOCl will proceed as a halogenation reaction, where the chlorine atom from NOCl will attach to one of the carbon atoms from the alkene double bond. Since this carbon-chlorine bond is more polar than a carbon-nitrogen bond, the nitrogen and oxygen atoms in NOCl will remain bonded together, and they will attach to the other carbon atom. This results in a product with the formula \(\mathrm{CH}_{3}\mathrm{CH}\mathrm{CH}_{2}\mathrm{ClNO}\).
03

Compare the given compounds to the expected product from step 2

We have determined that the product of the reaction should have the formula \(\mathrm{CH}_{3}\mathrm{CH}\mathrm{CH}_{2}\mathrm{ClNO}\). Comparing this formula to the given options, we can see that option (c) matches this formula.
04

Conclude

Therefore, the correct answer is option (c), as the product of the reaction between \(\mathrm{CH}_{3}\mathrm{CH}=\mathrm{CH}_{2}\) and \(\mathrm{NOCl}\) is \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHClNO}\).

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Most popular questions from this chapter

1-Pentyne reacts with \(40 \% \mathrm{H}_{2} \mathrm{SO}_{4}\) in the presence of \(1 \% \mathrm{HgSO}_{4}\) to give (a) Pentan-2-one (b) Pentan-1-ol (c) Pentan-2-ol (d) Pentan-3-one

The best method of preparation of an alkane with odd number of carbons from two alkylhalides is (a) Wurtz reaction (b) Kolbe's electrolysis (c) Corey-House synthesis (d) Ullmann reaction

An organic compound ( \(3.0 \mathrm{~g}\) ) gave on complete combustion, \(3.476 \mathrm{~g}\) of \(\mathrm{CO}_{2}\) and \(1.422 \mathrm{~g}\) of water. The molecular weight of the compound is 228 . Give molecular formula of the compound.

The maximum number of optical isomers produced on monochlorination of 2 -methylbutane will be (a) 2 (b) 3 (c) 4 (d) 1

Simplest alkane which can exhibit optical activity is (a) 3 -methyl hexane (b) 3 -methyl heptane (c) 2 -methyl butane (d) neopentane
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