Chapter 2: Problem 88
Which of the following alkenes will undergo acid catalysed hydration most readily? (a) (b) Cis-2-butene (c) trans-2-butene (d) 1 -butene
Chapter 2: Problem 88
Which of the following alkenes will undergo acid catalysed hydration most readily? (a) (b) Cis-2-butene (c) trans-2-butene (d) 1 -butene
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Get started for freeWhat are the products formed when buta-1, 3 -diene is treated with HBr in \(1: 1\) molar proportion? Explain the formation of the products.
HI does not exhibit peroxide effect because (a) HI is a reducing agent. (b) the iodine free radicals formed recombine readily to form the iodine molecule. (c) the bond energy of HI is very high that it does not undergo homolytic fission to give iodine radicals. (d) Free radical reactions work well when both the propagation steps are endothermic.
Directions: Each question contains Statement-1 and Statement-2 and has the following choices (a), (b), (c) and (d), out of which ONLY ONE is correct. (a) Statement- 1 is True, Statement- 2 is True; Statement- 2 is a correct explanation for Statement-1 (b) Statement- 1 is True, Statement- 2 is True; Statement- 2 is NOT a correct explanation for Statement-1 (c) Statement-1 is True, Statement- 2 is False (d) Statement- 1 is False, Statement- 2 is True Statement 1 Boiling point of n-pentane is higher than that of neopentane while the melting point of \(n\) -pentane is lower than that of neopentane. and Statement 2 Boiling point of alkanes depend upon the surface area while melting point depends upon the packing of molecules in the solid state. Neopentane fits into the crystal lattice more readily and it has minimum surface area compared to n-pentane.
Alkanes and alkenes can be prepared by (a) Wurtz reaction (b) Williamson synthesis (c) Dehydrohalogenation (d) Kolbe's electrolysis
Which of the following reactions give an alkyne? (a) sodium fumarate \(\frac{\text { Kolbe's }}{\text { electrolysis }}\) (b) \(\mathrm{CH}_{3} \mathrm{CBr}_{2} \mathrm{CHBr}_{2} \longrightarrow \underset{\mathrm{Zn} \text { /alcohol } / \Delta}{\longrightarrow}\) (c) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHBr}_{2} \stackrel{\mathrm{NaNH}_{2} / \Delta}{\longrightarrow}\) (d) \(\mathrm{CH}_{3} \mathrm{CHBr}-\mathrm{CH}_{2} \mathrm{Br} \stackrel{\mathrm{NaNH}_{2}}{\longrightarrow}\)
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