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Chapter 2: Problem 94

A compound that decolourizes alkaline \(\mathrm{KMnO}_{4}\) and gives a red precipitate with ammoniacal cuprous chloride is (a) 1 -butyne (b) 1 -pentene (c) 2 -butyne (d) 2-pentyne

Short Answer

Expert verified
Answer: (a) 1-butyne

Step by step solution

01

Reactions with alkaline \(\mathrm{KMnO}_{4}\)

Alkaline \(\mathrm{KMnO}_{4}\) is a strong oxidizing agent that oxidizes unsaturated hydrocarbons (such as alkenes and alkynes) to form more oxidized products. In the process, the purple color of the \(\mathrm{KMnO}_{4}\) solution is decolorized. Among the given compounds, only alkenes and alkynes will react with alkaline \(\mathrm{KMnO}_{4}\).
02

Reactions with ammoniacal cuprous chloride

Ammoniacal cuprous chloride is a reagent that reacts with terminal alkynes (alkynes with a triple bond at the end of the carbon chain) to form a red precipitate of copper acetylide. Therefore, among the given compounds, only terminal alkynes will give a red precipitate with ammoniacal cuprous chloride.
03

Analyzing the given compounds

Now, let's analyze the given compounds: a) 1-butyne: (Terminal alkyne) It will decolorize alkaline \(\mathrm{KMnO}_{4}\) and give a red precipitate with ammoniacal cuprous chloride. b) 1-pentene: (Alkene) It can decolorize alkaline \(\mathrm{KMnO}_{4}\) but will not give a red precipitate with ammoniacal cuprous chloride. c) 2-butyne: (Non-terminal alkyne) It can decolorize alkaline \(\mathrm{KMnO}_{4}\) but will not give a red precipitate with ammoniacal cuprous chloride. d) 2-pentyne: (Non-terminal alkyne) It can decolorize alkaline \(\mathrm{KMnO}_{4}\) but will not give a red precipitate with ammoniacal cuprous chloride.
04

Identifying the correct compound

Based on the analysis in step 3, only 1-butyne has the desired properties of decolorizing alkaline \(\mathrm{KMnO}_{4}\) and giving a red precipitate with ammoniacal cuprous chloride. Therefore, the correct answer is (a) 1-butyne.

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Most popular questions from this chapter

Which of the following is the correct statement? (a) Acetylene is less reactive than ethylene in electrophilic addition reaction. (b) The hydrolysis of \(\mathrm{Mg}_{2} \mathrm{C}_{3}\) (Magnesium carbide) produces acetylene. (c) Ozonolysis of acetylene produces \(\mathrm{CO}_{2}\) and \(\mathrm{H}_{2} \mathrm{O}\). (d) Reduction of dialkyl acetylene using Lindlar's catalyst gives a trans olefin.

The total number of chlorinated products given by ethane is (a) 6 (b) 7 (c) 8 (d) 9

Which of the following alkenes will undergo acid catalysed hydration most readily? (a) (b) Cis-2-butene (c) trans-2-butene (d) 1 -butene

The best method of preparation of an alkane with odd number of carbons from two alkylhalides is (a) Wurtz reaction (b) Kolbe's electrolysis (c) Corey-House synthesis (d) Ullmann reaction

Directions: Each question contains Statement-1 and Statement-2 and has the following choices (a), (b), (c) and (d), out of which ONLY ONE is correct. (a) Statement- 1 is True, Statement- 2 is True; Statement- 2 is a correct explanation for Statement-1 (b) Statement- 1 is True, Statement- 2 is True; Statement- 2 is NOT a correct explanation for Statement-1 (c) Statement-1 is True, Statement- 2 is False (d) Statement- 1 is False, Statement- 2 is True Statement 1 Oxymercuration reduction of an alkene gives an alcohol in which the -OH group is added to a more branched carbon of the double bond, while hydroboration- oxidation of an alkene gives an alcohol in which the -OH group is added to a less branched carbon of the alkene. and Statement 2 Hydration of an alkene in the presence of an acid is one of the standard methods of preparation of an alcohol form alkenes.
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