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Chapter 2: Problem 94

A compound that decolourizes alkaline \(\mathrm{KMnO}_{4}\) and gives a red precipitate with ammoniacal cuprous chloride is (a) 1 -butyne (b) 1 -pentene (c) 2 -butyne (d) 2-pentyne

Short Answer

Expert verified
Answer: (a) 1-butyne

Step by step solution

01

Reactions with alkaline \(\mathrm{KMnO}_{4}\)

Alkaline \(\mathrm{KMnO}_{4}\) is a strong oxidizing agent that oxidizes unsaturated hydrocarbons (such as alkenes and alkynes) to form more oxidized products. In the process, the purple color of the \(\mathrm{KMnO}_{4}\) solution is decolorized. Among the given compounds, only alkenes and alkynes will react with alkaline \(\mathrm{KMnO}_{4}\).
02

Reactions with ammoniacal cuprous chloride

Ammoniacal cuprous chloride is a reagent that reacts with terminal alkynes (alkynes with a triple bond at the end of the carbon chain) to form a red precipitate of copper acetylide. Therefore, among the given compounds, only terminal alkynes will give a red precipitate with ammoniacal cuprous chloride.
03

Analyzing the given compounds

Now, let's analyze the given compounds: a) 1-butyne: (Terminal alkyne) It will decolorize alkaline \(\mathrm{KMnO}_{4}\) and give a red precipitate with ammoniacal cuprous chloride. b) 1-pentene: (Alkene) It can decolorize alkaline \(\mathrm{KMnO}_{4}\) but will not give a red precipitate with ammoniacal cuprous chloride. c) 2-butyne: (Non-terminal alkyne) It can decolorize alkaline \(\mathrm{KMnO}_{4}\) but will not give a red precipitate with ammoniacal cuprous chloride. d) 2-pentyne: (Non-terminal alkyne) It can decolorize alkaline \(\mathrm{KMnO}_{4}\) but will not give a red precipitate with ammoniacal cuprous chloride.
04

Identifying the correct compound

Based on the analysis in step 3, only 1-butyne has the desired properties of decolorizing alkaline \(\mathrm{KMnO}_{4}\) and giving a red precipitate with ammoniacal cuprous chloride. Therefore, the correct answer is (a) 1-butyne.

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Most popular questions from this chapter

An ester on hydrolysis gave an acid which on Kolbe's electrolysis gave ethane. The ester is (a) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COO} \mathrm{CH}_{3}\) (b) (c) \(\mathrm{CH}_{3} \mathrm{COO} \mathrm{C}_{2} \mathrm{H}_{5}\) (d) \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{COO} \mathrm{C}_{2} \mathrm{H}_{5}\)

When \(\mathrm{n}\) -hexane is passed over heated alumina or chromic oxide catalyst under pressure, the product formed is (a) Iso hexane (b) cyclohexane (c) butane and ethane (d) Benzene

A reagent that can form a hydrocarbon with a Grignard reagent is (a) \(\mathrm{HCOOC}_{2} \mathrm{H}_{5}\) (b) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}\) (c) \(\mathrm{CH}_{3} \mathrm{COCH}_{3}\) (d) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COC}_{6} \mathrm{H}_{5}\)

The cis hydroxylation of alkenes can be effected by (a) reaction with \(\mathrm{OsO}_{4}\) (b) addition of Baeyer's reagent (c) reaction with \(\mathrm{H}_{2} \mathrm{O}_{2}\) and formic acid (d) reaction with an acid in the presence of water.

\(\mathrm{CH}_{3} \mathrm{COCH}_{2} \mathrm{CH}_{3}\) can be reduced to \(\mathrm{n}\) -butane when the reducing agent is (a) \(\mathrm{NaBH}_{4}\) (b) LiAlH (c) \(\mathrm{Zn}(\mathrm{Hg}) / \mathrm{HCl}\) (d) \(\mathrm{H}_{2} \mathrm{~S}\)
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