The IUPAC name of the compound is (a) 6-bromo-2-chlorocyclohexene (b) 3-bromo-1-chlorocyclohexene (c) 1 -bromo-3-chlorocyclohexene (d) 2-bromo-6-chlorocyclohexene

Short Answer

Expert verified
a) 6-bromo-2-chlorocyclohexene b) 3-bromo-1-chlorocyclohexene c) 1-bromo-3-chlorocyclohexene d) 2-bromo-6-chlorocyclohexene Answer: c) 1-bromo-3-chlorocyclohexene

Step by step solution

01

Identify the parent chain

In this case, the parent chain is cyclohexene, which is a 6-membered ring with one double bond. All of the options have this as their base name, so we can continue to the next step.
02

Assign numbering to the substituents

We have two substituents: bromine (Br) and chlorine (Cl). According to IUPAC naming rules, the lower locant number should be assigned to the substituent nearest to the double bond of cyclohexene. If there is a tie, then the alphabetical order should break that tie. We analyze each option: (a) 6-bromo-2-chlorocyclohexene: Here, bromine is at the 6th position, and chlorine is at the 2nd position. (b) 3-bromo-1-chlorocyclohexene: Bromine is at the 3rd position and chlorine is at the 1st position. In this case, the chlorine is closest to the double bond, which is preferable according to the naming rules. (c) 1-bromo-3-chlorocyclohexene: Bromine is at the 1st position, and chlorine is at the 3rd position. Here, bromine is closest to the double bond. (d) 2-bromo-6-chlorocyclohexene: Bromine is at the 2nd position, and chlorine is at the 6th position.
03

Choose the correct option based on numbering and alphabetical order

After analyzing the numbers assigned to the substituents in each option and checking the alphabetical order rule, the correct choice should be (c) 1-bromo-3-chlorocyclohexene. In this option, the bromine is closest to the double bond and it is also consistent with alphabetical order rules. So, the IUPAC name of the given compound is 1-bromo-3-chlorocyclohexene.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Directions: Each question contains Statement-1 and Statement-2 and has the following choices (a), (b), (c) and (d), out of which ONLY ONE is correct. (a) Statement- 1 is True, Statement- 2 is True; Statement- 2 is a correct explanation for Statement-1 (b) Statement- 1 is True, Statement- 2 is True; Statement- 2 is NOT a correct explanation for Statement-1 (c) Statement-1 is True, Statement- 2 is False (d) Statement- 1 is False, Statement- 2 is True Statement 1 Erythro-2,3-dibromobutane on reaction with zinc and alcohol gives trans 2 -butene. and Statement 2 Elimination requires trans periplanar geometry.

1,6 Dibromohexane can be converted to cyclohexane, when treated with \(\mathrm{Na}\) or \(\mathrm{Zn}\), in the presence of a catalyst. This reaction is known as (a) Wurtz coupling (b) Dieckmann cyclization (c) Freund's method (d) Diels Alder reaction

When propyne reacts with excess of chlorine water, the product obtained is (a) 1,1 -dichloro propan-2-one (b) 1,1 -dichloropropan-2-ol (c) 2,2 -dichloropropan- 1 -al (d) 1,2 -dichloropropane

Alkynes are less reactive than alkenes towards electrophilic reagents. But the alkyne chemistry is useful for organic synthesis, in the form of hydration of the triple bond, formation of metalacetylides, selective reduction of alkynes and few other related reactions. Acetylene and HCHO react together in the presence of \(\mathrm{NaOCH}_{3}\) to give (a) \(\mathrm{CH}_{2}=\mathrm{CH}-\mathrm{OH}\) (b) \(\mathrm{H}_{2} \mathrm{C}=\mathrm{CH}-\mathrm{CH}_{2} \mathrm{OH}\) (c) \(\mathrm{HOH}_{2} \mathrm{C}-\mathrm{C} \equiv \mathrm{C}-\mathrm{CH}_{2} \mathrm{OH}\) (d) \(\mathrm{CH}_{3}-\mathrm{CHOH}-\mathrm{CHOH}-\mathrm{CH}_{3}\)

A reagent that can form a hydrocarbon with a Grignard reagent is (a) \(\mathrm{HCOOC}_{2} \mathrm{H}_{5}\) (b) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}\) (c) \(\mathrm{CH}_{3} \mathrm{COCH}_{3}\) (d) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COC}_{6} \mathrm{H}_{5}\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free