The major product obtained by the mononitration of \(\mathrm{C}_{6} \mathrm{H}_{5}-\mathrm{NH}-\mathrm{SO}_{2}-\mathrm{C}_{6} \mathrm{H}_{5}\) is

Short Answer

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Answer: The major product of mononitration of diphenyl sulfonamide is \(\mathrm{C}_{6}\mathrm{H}_{4}(\mathrm{NO}_{2})-\mathrm{NH}-\mathrm{SO}_{2}-\mathrm{C}_{6}\mathrm{H}_{5}\), with the nitro group in the para position with respect to the amine group.

Step by step solution

01

Identify the directing nature of the functional groups

In this compound, we have two functional groups, amine (NH) and sulfonamide (SO2). Amines are considered ortho-/para-directing groups due to the presence of a lone pair of electrons on the nitrogen atom, which can donate electron density to the benzene ring and make the ortho and para positions more prone to electrophilic attack. On the other hand, the sulfonamide group is meta-directing because the sulfur atom withdraws electron density through resonance, leading to electron-deficient ortho and para positions.
02

Determine the major product of mononitration

Since the amine group is ortho-/para-directing and the sulfonamide group is meta-directing, we have a conflicting situation. However, the amine group will have a greater influence on the electrophilic aromatic substitution, as the electron donation generally overpowers the electron-withdrawing effect. Thus, the major product will have the nitro group added to either the ortho or para position with respect to the amine (NH) group.
03

Analyze steric hindrance for final product prediction

Although the ortho and para positions are both electrophilic sites for the amine group, the para position is less sterically hindered than the ortho position. Therefore, the major product of the mononitration will have the nitro group added to the para position of the benzene ring connected to the amine group. The major product obtained by the mononitration of \(\mathrm{C}_{6}\mathrm{H}_{5}-\mathrm{NH}-\mathrm{SO}_{2}-\mathrm{C}_{6}\mathrm{H}_{5}\) is \(\mathrm{C}_{6}\mathrm{H}_{4}(\mathrm{NO}_{2})-\mathrm{NH}-\mathrm{SO}_{2}-\mathrm{C}_{6}\mathrm{H}_{5}\), with the nitro group in the para position with respect to the amine group.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mononitration of Benzene
The process of mononitration of benzene is a classic example of electrophilic aromatic substitution, a reaction in which benzene acts as a nucleophile to substitute one of its hydrogen atoms for an electrophile, in this case, a nitro group (\textbf{NO}\(_2\)). Here's how it works:

Firstly, a nitrating mixture, typically composed of nitric acid (\textbf{HNO}\(_3\)) and sulfuric acid (\textbf{H}\(_2\)\textbf{SO}\(_4\)), generates the active nitronium ion (\textbf{NO}\(_2^+\)). Next, benzene, with its high electron density and stable pi-electron cloud, forms a complex with the electrophilic nitronium ion. This electrophile attacks one of the hydrogen atoms on the benzene ring and temporarily disrupts the aromatic system, generating an intermediate species. Finally, the aromaticity is restored when the hydrogen proton is removed, resulting in the substituted product, nitrobenzene.

It's crucial that this reaction happens under controlled conditions because the presence of excess nitric acid could lead to further substitution, giving di- or trinitro compounds instead of the desired mononitro derivative.
Ortho-/Para-Directing Groups
Within the scope of electrophilic aromatic substitution reactions, ortho-/para-directing groups significantly influence the final position of the introduced electrophile on the benzene ring. These are groups that, due to the presence of lone pair electrons or an electronegative element, can donate electron density through resonance. This action enriches the ortho and para positions with electrons and makes them more attractive to incoming electrophiles.

Examples include functional groups such as \textbf{-OH}, \textbf{-OCH}\(_3\), and \textbf{-NH}\(_2\). When these groups are present on a benzene ring, they increase the likelihood of the electrophile attaching at either the position adjacent to (ortho) or opposite (para) the functional group. The ability for these groups to activate the ring is why they're termed 'activating groups.' Besides resonance, inductive effects can also play a role, where electron-donating groups release electron density into the ring through sigma bonds.

The ortho-/para-directing nature of a group can be a competitive factor when designing synthesis pathways, as other substituents on the benzene can affect the expected outcome of a reaction.
Steric Hindrance in Nitration
When considering the mononitration of a complex molecule with multiple functional groups, we must assess steric hindrance in nitration. Steric hindrance occurs when the size of groups attached to the benzene ring interferes with the approach of the electrophile. This is a physical obstruction rather than an electronic effect, affecting the reaction's outcome by making certain positions on the ring less accessible.

In step 3 of our step-by-step solution, we determined that the para position was less sterically hindered, leading to the major product having a nitro group at this location. This is a common theme in nitration reactions, where the bulkier ortho position is often less favored. The presence of large substituents could completely inhibit reaction at the ortho position, making the para product the most favorable and sometimes the only possible product.

Understanding steric hindrance is key in predicting reaction outcomes, especially since it does not rely solely on electronic effects. It's a practical consideration that's crucial for obtaining high yields of the desired product in synthetic chemistry.

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Most popular questions from this chapter

Statement 1 Fluorine deactivates benzene ring more than other halogens when attached to the benzene ring. and Statement 2 Fluorine in fluorobenzene is an ortho, para directing group.

Identify the wrong statement among the following related to phenol. (a) Phenol is a weaker acid than carbonic acid. (b) When distilled with zinc, phenol gives benzene. (c) Among the three isomers of nitrophenol, the one that is least soluble in water is \(\mathrm{p}\) -nitrophenol. (d) Formation of phenol from chlorobenzene is an example of nucleophilic aromatic substitution.

The wrong statement relating to the influence of substituents on aromatic electrophilic substitution reactions is (a) The rate determining step in an electrophilic substitution is the one which leads to the formation of an arenium ion. (b) Electron releasing groups make the transition state more stable and the transition state resembles the arenium ion. (c) The arenium ion is a highly energetic intermediate and the step that leads to it is a highly exothermic step. (d) An electron withdrawing substituent makes the arenium ion less stable and the transition state leading to such an arenium ion is less stable.

Sodium phenoxide when heated with \(\mathrm{CO}_{2}\) under pressure gives sodium salicylate. This reaction is known as (a) Reimer-Tiemann reaction (b) Schotten-Baumann reaction (c) Williamson's synthesis (d) Kolbe's reaction

The product P formed in the following reaction is \(\mathrm{C}_{6} \mathrm{H}_{6}+\mathrm{CH}_{2}=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}_{2} \stackrel{\mathrm{HF}}{\stackrel{0^{\circ} \mathrm{C}}}{\longrightarrow} \mathrm{P}\) (a) \(\mathrm{C}_{6} \mathrm{H}_{5}-\mathrm{CH}_{2}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{3}\) (b) \(\mathrm{C}_{6} \mathrm{H}_{5}-\mathrm{CH}=\mathrm{CH}_{2}\) (c) CC=C(C)CCC (d) \(\mathrm{C}_{6} \mathrm{H}_{5}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{CH}=\mathrm{CH}_{2}\)

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