The reagent used to convert phenol to quinol is (a) \(\mathrm{KMnO}_{4} / \mathrm{H}_{2} \mathrm{SO}_{4}\) (c) \(\mathrm{K}_{2} \mathrm{~S}_{2} \mathrm{O}_{8}\) followed by acidification

Short Answer

Expert verified
(a) KMnO4 / H2SO4 (b) K2S2O8 followed by acidification Answer: (b) K2S2O8 followed by acidification

Step by step solution

01

Determine the products of phenol reacting with the given reagents

We will determine the products formed upon reaction of phenol with the given two reagents in separate cases.
02

Case 1: Phenol reaction with \(\mathrm{KMnO}_{4} / \mathrm{H}_{2} \mathrm{SO}_{4}\)

\(\mathrm{KMnO}_{4}\) is a strong oxidizing agent and it can oxidize phenol to produce a benzoquinone. The reaction is as follows: C\(_6\)H\(_5\)OH + 2 KMnO\(_4\) + 3 H\(_2\)SO\(_4\) \(\longrightarrow\) C\(_6\)H\(_4\)O\(_2\) + 2 MnSO\(_4\) + 8 H\(_2\)O + K\(_2\)SO\(_4\) In this reaction, the quinol is not formed.
03

Case 2: Phenol reaction with \(\mathrm{K}_{2} \mathrm{~S}_{2} \mathrm{O}_{8}\) followed by acidification

\(\mathrm{K}_{2} \mathrm{~S}_{2} \mathrm{O}_{8}\) is a peroxydisulfate oxidizing agent. It can oxidize phenol to form ortho-quinol as a major product. The reaction is as follows: C\(_6\)H\(_5\)OH + \(\mathrm{K}_{2} \mathrm{~S}_{2} \mathrm{O}_{8}\) \(\longrightarrow\) C\(_6\)H\(_{4}\)(OH)\(_2\) + \(\mathrm{K}_{2} \mathrm{~SO}_{4}\) In this reaction, the ortho-quinol is formed as a product.
04

Select the correct reagent for converting phenol into quinol

According to the reactions mentioned above, the reagent that successfully converts phenol into quinol is: (c) \(\mathrm{K}_{2} \mathrm{~S}_{2} \mathrm{O}_{8}\) followed by acidification

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