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Chapter 3: Problem 158

\(\frac{\mathrm{CCl}_{3} \mathrm{CHO}}{\mathrm{K}_{2} \mathrm{CO}_{3}} \rightarrow\) (A) \(\frac{\mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}}{\mathrm{NaOH}} \longrightarrow(\mathrm{B}) .\) The major product (b) is

Short Answer

Expert verified
Answer: The product of the reaction between chloral hydrate and reagent (A) is trichloroacetic acid (Cl₃C-COOH).

Step by step solution

01

Identify the initial compound

The given initial compound, \(\frac{\mathrm{CCl}_{3} \mathrm{CHO}}{\mathrm{K}_{2} \mathrm{CO}_{3}}\), is chloral hydrate, with a trichloromethyl group and an aldehyde group. It has the following structure: Cl₃C-CHO
02

Reaction with Reagent (A)

Reagent (A) consists of sodium dichromate (Na2Cr2O7) and sodium hydroxide (NaOH) in a basic solution. This combination of reagents is consistent with a chromic acid oxidation reaction. In this reaction, the aldehyde functional group in chloral hydrate (Cl₃C-CHO) will be oxidized to a carboxylic acid, while the trichloromethyl group remains unaffected by this reaction. The resulting product is trichloroacetic acid (Cl₃C-COOH).
03

Identify Reagent (B)

The exercise does not provide information about reagent (B). In order to determine the major product that results from the reaction with reagent (B), we would need more information about its nature and reactivity.
04

Conclusion

Without information about reagent (B), it is not possible to fully determine the major product of the reaction sequence. We were, however, able to determine that the product of the reaction with reagent (A) is trichloroacetic acid (Cl₃C-COOH).

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