Chapter 3: Problem 161
The product P formed in the following reaction is \(\mathrm{C}_{6}
\mathrm{H}_{6}+\mathrm{CH}_{2}=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}_{2}
\stackrel{\mathrm{HF}}{\stackrel{0^{\circ} \mathrm{C}}}{\longrightarrow}
\mathrm{P}\)
(a) \(\mathrm{C}_{6}
\mathrm{H}_{5}-\mathrm{CH}_{2}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{3}\)
(b) \(\mathrm{C}_{6} \mathrm{H}_{5}-\mathrm{CH}=\mathrm{CH}_{2}\)
(c)
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.