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Chapter 3: Problem 165

p-cresol on heating with zinc dust gives (a) benzene (b) toluene (c) \(\mathrm{p}\) -xylene (d) benzaldehyde

Short Answer

Expert verified
Answer: (b) toluene

Step by step solution

01

Identify the reactants

p-Cresol is an aromatic compound with the chemical formula \(\mathrm{C}_{7}\mathrm{H}_{8}\mathrm{O}\). Its structure consists of an aromatic benzene ring with a hydroxyl (-OH) group and a methyl (-CH3) group in the para position (opposite each other in the benzene ring). The other reactant is zinc dust, which is a metal commonly used as a reducing agent in various chemical reactions.
02

React p-cresol with zinc dust

Zinc dust acts as a reducing agent and is used to remove the oxygen from the hydroxyl group in p-cresol, leaving a hydrogen atom in its place: $$\mathrm{Zn} + \mathrm{C}_{7}\mathrm{H}_{8}\mathrm{O} \rightarrow \mathrm{C}_{7}\mathrm{H}_{8} + \mathrm{ZnO}$$ This reaction is essentially the removal of the hydroxyl group (-OH) from p-cresol and its reduction to a hydrogen atom.
03

Determine the product obtained

After the reaction, the product formed is a compound with the chemical formula \(\mathrm{C}_{7}\mathrm{H}_{8}\), which is toluene (a benzene ring with a single methyl group attached). Therefore, the correct answer is: (b) toluene

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Most popular questions from this chapter

Statement 1 Phenol reacts with \(\mathrm{PCl}_{5}\) to give only a small amount of chlorobenzene, the main product is triphenyl phosphate \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}\right)_{3} \mathrm{P}=\mathrm{O}\) or \(\left(\mathrm{C}_{6} \mathrm{H}_{5}\right)_{3} \mathrm{PO}_{4}\) and Statement 2 \(\mathrm{C}-\mathrm{O}\) bond in phenol has partial double bond character.

$$ \begin{array}{l} \text { The organic product (X) formed in the following reaction is }\\\ \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{Cl}+\mathrm{C}_{6} \mathrm{H}_{5} \stackrel{\mathrm{AICl}_{3}}{\longrightarrow} \mathrm{X} \end{array} $$

When phenol is treated with ethylene oxide in presence of acid the major product is

The increasing order of acid strength of 4-Methoxyphenol (I), 4Nitrophenol (II) and 4-Methylphenol (III) is (a) \(\mathrm{III}<\mathrm{I}<\mathrm{II}\) (b) \(\mathrm{I}<\mathrm{II}<\mathrm{III}\) (c) \(I<\mathrm{III}<\mathrm{II}\) (d) \(\mathrm{III}<\mathrm{II}<\mathrm{I}\)

Statement 1 Phenol gives p-bromophenol as the major product when treated \(\mathrm{Br}_{2}\) dissolved in carbon disulphide at low temperature. and Statement 2 p-Bromophenol has lower \(\mathrm{pK}_{\text {a }}\) value than phenol.
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