The major product formed when o-cresol is treated with \(\mathrm{Br}_{2}\) in \(\mathrm{CS}_{2}\) at ice cold conditions is

Short Answer

Expert verified
Answer: The major product formed in this reaction is 2-bromo-o-cresol.

Step by step solution

01

Identify the electrophile and nucleophile

In an electrophilic aromatic substitution reaction, the benzene ring acts as a nucleophile, attacking an electrophile. Here, the electrophile is the bromine ion (\(\mathrm{Br}^{+}\)) formed from the \(\mathrm{Br}_{2}\). The nucleophile is the aromatic ring of the o-cresol molecule.
02

Analyze the directing influence of the hydroxyl group

In the o-cresol molecule, the hydroxyl group (OH) is an ortho/para director. It can activate the carbon atoms in the ortho and para positions on the benzene ring, making them more susceptible to electrophilic attack. Because the reaction takes place under ice cold conditions, it is likely that the reaction will proceed faster at the ortho position.
03

Determine the ortho-substituted product

Under these conditions, the o-cresol molecule undergoes electrophilic substitution with the bromine ion at the ortho position, forming a new C-Br bond. The new compound will have the hydroxyl group (OH) at one position, and the bromine atom (Br) at the adjacent carbon atom on the benzene ring. This compound is called 2-bromo-o-cresol.
04

Conclusion

The major product formed when o-cresol is treated with \(\mathrm{Br}_{2}\) in \(\mathrm{CS}_{2}\) at ice cold conditions is the ortho-substituted product, 2-bromo-o-cresol.

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