Chapter 3: Problem 2
How can benzene be converted to m-dibromobenzene?
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chapter 3: Problem 2
How can benzene be converted to m-dibromobenzene?
These are the key concepts you need to understand to accurately answer the question.
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Get started for freeThe product formed when phenol is treated with \(\mathrm{H}_{2} / \mathrm{Ni}\) at \(475^{\circ} \mathrm{C}\) is (a) Cyclohexanol (b) Toluene (c) Cyclohexane (d) Cyclopentane
Column I \(\quad\) Column II (a) \(\mathrm{C}_{6} \mathrm{H}_{6}+\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}_{2} \stackrel{\mathrm{H}_{2} \mathrm{SO}_{4}}{\longrightarrow}\) (p) Schotten-Baumann reaction (b) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}+\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COCl} \stackrel{\mathrm{NaOH}}{\longrightarrow}\) (q) Friedel-Crafts reaction (c) \(\mathrm{C}_{6} \mathrm{H}_{6}+\stackrel{\mathrm{AlCl}_{3}}{\longrightarrow}\) (r) Reimer-Tiemann reaction (d) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH} \frac{{ }_{5}^{(\mathrm{i}) \mathrm{CCl}_{4} / \mathrm{NaOH}}}{{ }_{(\text {iii }) \mathrm{H}_{3} \mathrm{O}^{+}}}{\longrightarrow}\) (s) Isopropyl benzene (t) Electrophilic substitution
\(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}+\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COCl} \rightarrow \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OCOC}_{6} \mathrm{H}_{5}+\mathrm{HCl}\). This reaction is called (a) Schotten-Baumann reaction (b) Perkin reaction (c) Schmidt reaction (d) Claisen reaction
Why is pyrrole a much weaker base than pyridine?
Phenol is less acidic than (a) water (b) ethanol (c) p-nitrophenol (d) p-methoxyphenol
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