Statement 1 o-Hydroxy benzene sulphonic acid on heating to \(373 \mathrm{~K}\) changes to p-Hydroxybenzene sulphonic acid. and Statement 2 Sulphonation of phenol is a reversible process.

Short Answer

Expert verified
The sulphonation of phenol is a reversible process because it proceeds via a protonated phenol intermediate that can be attacked by water to give phenol again, allowing an equilibrium to exist in the system. This reversibility depends on the concentration and reaction conditions.

Step by step solution

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Statement 1: Conversion of o-Hydroxybenzene Sulphonic Acid to p-Hydroxybenzene Sulphonic Acid at 373 K

The given exercise states that o-Hydroxybenzene sulphonic acid, when heated to 373 K, changes to p-Hydroxybenzene sulphonic acid. This is because the sulphonation of phenol is highly temperature sensitive. Step 1: Write the reaction of sulphonation of phenol with sulfuric acid \[C_6H_5OH + H_2SO_4 \rightarrow C_6H_5OHSO_3H + H_2O\] Step 2: Indicate the positions of o-Hydroxybenzene sulphonic acid (ortho position) and p-Hydroxybenzene sulphonic acid (para position) Ortho position: -OHSO_3H group is attached to the carbon atom adjacent to the -OH group. Para position: -OHSO_3H group is attached to the carbon atom opposite to the -OH group. Step 3: State the reason for the conversion at 373 K At high temperatures, sterics become less important, and the preferred product is p-Hydroxybenzene sulphonic acid due to its higher stability compared to the o-Hydroxybenzene sulphonic acid.
02

Statement 2: Sulphonation of Phenol is a Reversible Process

The sulphonation of phenol is a reversible process, which means it can go back to its reactant form. This is because the reaction proceeds via a protonated phenol intermediate that can be attacked by water to give phenol. Step 1: Write the forward and reverse reactions \[C_6H_5OH + H_2SO_4 \rightleftharpoons C_6H_5OHSO_3H + H_2O\] Step 2: Describe the intermediate formation - Protonated phenol intermediate is formed when sulfuric acid protonates the phenol: \(C_6H_5OH + H_2SO_4 \rightarrow C_6H_5OH_2^+ + HSO_4^-\). - The protonated phenol intermediate can be attacked by the bisulfate ion to give o/p-Hydroxybenzene sulphonic acids: \(C_6H_5OH_2^+ \rightarrow C_6H_5OHSO_3H\). Step 3: Explain the reversibility using the intermediate - The intermediate protonated phenol can accept a water molecule and form phenol again by reversing the reaction: \(C_6H_5OH_2^+ + H_2O \rightarrow C_6H_5OH + H_3O^+\) - This reversibility of the reaction allows the equilibrium in the system and depends on the concentration and reaction conditions. In conclusion, we analyzed the conversion of o-Hydroxybenzene sulphonic acid to p-Hydroxybenzene sulphonic acid at 373 K and explained why the sulphonation of phenol is a reversible process.

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