Chapter 3: Problem 24
The product formed when phenol is heated with salicylic acid in the presence of phosphoryl chloride is (a) aspirin (b) salol (c) anisole (d) gallic acid
Chapter 3: Problem 24
The product formed when phenol is heated with salicylic acid in the presence of phosphoryl chloride is (a) aspirin (b) salol (c) anisole (d) gallic acid
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Get started for freeThe increasing order of acid strength of 4-Methoxyphenol (I), 4Nitrophenol (II) and 4-Methylphenol (III) is (a) \(\mathrm{III}<\mathrm{I}<\mathrm{II}\) (b) \(\mathrm{I}<\mathrm{II}<\mathrm{III}\) (c) \(I<\mathrm{III}<\mathrm{II}\) (d) \(\mathrm{III}<\mathrm{II}<\mathrm{I}\)
Reaction of nitrobenzene with chlorine in presence of \(\mathrm{FeCl}_{3}\) gives m-chloronitrobenzene as the major product. Which of the following statement(s) is/are correct regarding the formation of the meta isomer? (a) Nitro group increases the electron density at the meta position of the benzene ring. (b) Nitro group withdraws electron mainly from ortho and para position by resonance and hence meta position becomes position of comparatively higher electron density (c) The intermediate arenium ion formed by the initial attack of \(\mathrm{Cl}^{+}\) at the meta position is more stable compared to that formed by attack at ortho and para positions. (d) Loss of aromaticity occurs when Cl' attacks at the ortho and para positions and not at the meta position.
Which of the following reagents can effect hydroxylation at an aromatic carbon? (a) aqueous KOH (b) alcoholic KOH (c) alkaline \(\mathrm{KMnO}_{4}\) (d) Fenton's reagent
Mononitration of biphenyl by treating with nitrating mixture gives mainly
When phenol reacts with dilute neutral \(\mathrm{FeCl}_{3}\) solution, a violet colouration is produced. The structure of the violet coloured species is (a) \(\left[\mathrm{Fe}\left(\mathrm{OC}_{6} \mathrm{H}_{5}\right)_{6}\right]^{4}\) (b) \(\mathrm{Fe}\left(\mathrm{C}_{6} \mathrm{H}_{5}\right)_{3}\) (c) \(\left[\mathrm{Fe}\left(\mathrm{OC}_{6} \mathrm{H}_{5}\right)_{6}\right]^{3-}\) (d) \(\left(\mathrm{FeCl}_{3}\right)\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}\right)\)
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