Chapter 3: Problem 6
Phenol is an acid but does not react with saturated \(\mathrm{NaHCO}_{3}\) solution. Why is it so?
Chapter 3: Problem 6
Phenol is an acid but does not react with saturated \(\mathrm{NaHCO}_{3}\) solution. Why is it so?
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Get started for freeThe wrong statement relating to the influence of substituents on aromatic electrophilic substitution reactions is (a) The rate determining step in an electrophilic substitution is the one which leads to the formation of an arenium ion. (b) Electron releasing groups make the transition state more stable and the transition state resembles the arenium ion. (c) The arenium ion is a highly energetic intermediate and the step that leads to it is a highly exothermic step. (d) An electron withdrawing substituent makes the arenium ion less stable and the transition state leading to such an arenium ion is less stable.
Which of the following statement(s) is/are correct? (a) Benzene on heating with air in presence of vanadium pentoxide at \(700 \mathrm{~K}\) gives maleic anhydride (b) There is no kinetic isotope effect for nitration of benzene. (c) Benzene hexachloride is an unsaturated compound. (d) Distillation of o-cresol and \(\mathrm{p}\) -cresol with zinc dust gives the same product.
Ethyl benzene \(\stackrel{\mathrm{NBS}}{\longrightarrow} \mathrm{A} \stackrel{\text { alc.KOH }}{\longrightarrow} \mathrm{B}\). The product \(\mathrm{B}\) in the above reaction sequence is (a) styrene (b) 1 -phenyl ethanol (c) 2 -phenyl ethanol (d) p-ethylphenol
Neopentyl bromide reacts with benzene under Friedel-Crafts conditions to give mainly
An organic compound having the molecular formula \(\mathrm{C}_{7} \mathrm{H}_{8} \mathrm{O}\) is insoluble in \(\mathrm{NaHCO}_{3}\) solution but dissolves in aqueous \(\mathrm{NaOH}\). When treated with bromine water the compound rapidly forms a precipitate having the molecular formula \(\mathrm{C}_{7} \mathrm{H}_{5} \mathrm{OBr}_{3} .\) The organic compound is (a) o-cresol (b) \(\mathrm{m}\) -cresol (c) \(\mathrm{p}\) -cresol (d) anisole
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