When phenol reacts with diazomethane \(\left(\mathrm{CH}_{2} \mathrm{~N}_{2}\right)\), the products formed are

The reactants in this reaction are phenol and diazomethane (CH2N2). Phenol is an aromatic compound with a hydroxyl group attached to a benzene ring. Its structure can be represented as follows: Phenol: O ║ C // \\ CC CC ║ ║ CC CC \\ // C \ H Diazomethane (CH2N2): H | C | N ║ N

The reaction between phenol and diazomethane proceeds via a nucleophilic attack of the oxygen atom from phenol to carbon atom in diazomethane. This leads to the formation of an intermediate species. The reaction mechanism can be described as follows: Phenol Diazomethane Intermediate (Oxygen nucleophile) + (Electrophilic Carbon) -> (Oxygen attached to Carbon with nitrogen) O ║ C H // \\ + CH2N2 -> O CC CC ║ ║ ║ C CC CC | \\ // CH2N2

After the formation of the intermediate species, nitrogen gas (N2) is released from diazomethane. The phenol is now attached to the CH2 group (a methyl group). This forms the O-methyl ether derivative of phenol, known as anisole. The overall reaction equation can be written as: Phenol + Diazomethane -> Anisole + Nitrogen gas C6H5OH + CH2N2 -> C6H5OCH3 + N2

Anisole is an aromatic ether with a methoxy group attached to a benzene ring. Its structure can be represented as follows: Anisole: O ║ C // \\ CC CC ║ ║ CC CC \\ // C | H This concludes the step-by-step solution for the reaction between phenol and diazomethane. The products formed are anisole (C6H5OCH3) and nitrogen gas (N2).