Directions: This section contains multiple choice questions. Each question has 4 choices (a), (b), (c) and (d), out of which ONLY ONE is correct. The compound that gives a tertiary alcohol on reaction with \(\mathrm{CH}_{3} \mathrm{MgI}\) is

Short Answer

Expert verified
Answer: A ketone with two R groups attached to the carbonyl carbon.

Step by step solution

01

Understanding Grignard Reagents Reaction Mechanism

Grignard reagents, such as \(\mathrm{CH}_{3}\mathrm{MgI}\), are organometallic compounds that are highly nucleophilic due to the polarization of the carbon-metal (carbon-magnesium) bond. In a Grignard reagent, the carbon is partially negative, and the metal (Mg) is partially positive. The Grignard reagent can act as a nucleophile, attacking electrophilic carbon centers, most notably those in carbonyl compounds. When a Grignard reagent reacts with a carbonyl compound, an alkoxide is formed, which upon being treated with a proton source gives an alcohol.
02

Identify the Type of Carbonyl Compound that Would Yield a Tertiary Alcohol

Since we are asked to determine which compound gives a tertiary alcohol upon reaction with the Grignard reagent, we need to identify the type of carbonyl compound that would yield a tertiary alcohol after the nucleophilic attack by \(\mathrm{CH}_{3}\mathrm{MgI}\). Tertiary alcohols are those where the hydroxyl group is attached to a carbon atom bonded to three other carbon atoms. To achieve this, the carbonyl compound should be a ketone with two R groups attached to the carbonyl carbon that can accept the additional methyl group from the Grignard reagent to form a tertiary alcohol.
03

Choose the Correct Option

Unfortunately, there are no options provided for this question. However, we have determined that the compound that would give a tertiary alcohol on reaction with \(\mathrm{CH}_{3}\mathrm{MgI}\) should be a ketone with two R groups attached to the carbonyl carbon.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free