Directions: Each question contains Statement- 1 and Statement-2 and has the following choices (a), (b), (c) and (d), out of which ONLY ONE is correct. (a) Statement- 1 is True, Statement- 2 is True; Statement- 2 is a correct explanation for Statement- 1 (b) Statement- 1 is True, Statement- 2 is True; Statement- 2 is NOT a correct explanation for Statement- 1 (c) Statement- 1 is True, Statement- 2 is False (d) Statement- 1 is False, Statement- 2 is True Statement 1 \(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{O}-\mathrm{CH}_{2} \mathrm{Br}\) undergoes hydrolysis faster than \(\mathrm{CH}_{3}-\mathrm{O}-\mathrm{CH}_{2}-\mathrm{CH}_{2} \mathrm{Br}\) and Statement 2 The carbocation formed by ionization of \(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{OCH}_{2} \mathrm{Br}\) is stabilized by resonance.

Short Answer

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a) Statement- 1 is True, Statement- 2 is True; Statement- 2 is a correct explanation for Statement- 1. b) Statement- 1 is True, Statement- 2 is True; Statement- 2 is NOT a correct explanation for Statement- 1. c) Statement- 1 is True, Statement- 2 is False. d) Statement- 1 is False, Statement- 2 is True. Answer: a) Statement- 1 is True, Statement- 2 is True; Statement- 2 is a correct explanation for Statement- 1.

Step by step solution

01

Examine the Hydrolysis Reaction

The hydrolysis reaction typically involves breaking down a compound (in this case an organic compound) in the presence of water. We need to compare the reaction rates of CH3-CH2-O-CH2Br and CH3-O-CH2-CH2Br in the hydrolysis reaction.
02

Compare Reaction Rates

To compare the reaction rates, we must consider the following factors: - Stability of the intermediates formed in the reactions - Electronic effects that can stabilize the intermediates Comparing CH3-CH2-O-CH2Br and CH3-O-CH2-CH2Br, we can see that the difference between these two compounds is the position of the oxygen atom in the organic chain.
03

Analyze the Carbocation Formation of Statement 2

Let's focus on the carbocation formation of CH3-CH2-OCH2Br and study its stability. When CH3-CH2-OCH2Br undergoes hydrolysis and loses a bromide ion, it forms a carbocation: \((CH_3-CH_2-O-CH_2)^+\). This carbocation can be stabilized through resonance as the positive charge can be delocalized between the oxygen and carbon atoms, which increases the stability of the ions and leads to a faster hydrolysis reaction.
04

Determine the Correctness and Relation of the Statements

Based on our analysis, we can determine the following: - Statement 1 is true as CH3-CH2-O-CH2Br undergoes hydrolysis at a faster rate due to the factors we analyzed. - Statement 2 is also true as the carbocation formed by ionization of CH3-CH2-OCH2Br is stabilized by resonance. Now, we must determine how these statements are related. Since the stability of the carbocation through resonance explains why CH3-CH2-O-CH2Br undergoes hydrolysis faster than CH3-O-CH2-CH2Br, we can conclude that Statement 2 is a correct explanation for Statement 1. Therefore, the correct choice is (a) Statement- 1 is True, Statement- 2 is True; Statement- 2 is a correct explanation for Statement- 1.

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