Chapter 4: Problem 66
On boiling 2,2 -dichloropropane with aqueous alkali, the product obtained is (a) 2,2-propanediol (b) acetone (c) propanal (d) 2 -chloro-2-propanol
Chapter 4: Problem 66
On boiling 2,2 -dichloropropane with aqueous alkali, the product obtained is (a) 2,2-propanediol (b) acetone (c) propanal (d) 2 -chloro-2-propanol
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Get started for freeDirections: Each question contains Statement- 1 and Statement-2 and has the following choices (a), (b), (c) and (d), out of which ONLY ONE is correct. (a) Statement- 1 is True, Statement- 2 is True; Statement- 2 is a correct explanation for Statement- 1 (b) Statement- 1 is True, Statement- 2 is True; Statement- 2 is NOT a correct explanation for Statement- 1 (c) Statement- 1 is True, Statement- 2 is False (d) Statement- 1 is False, Statement- 2 is True Statement 1 Fluorobenzene undergoes nucleophilic substitution much faster than chlorobenzene. and Statement 2 Eluorine being more electronegative causes more decrease in electron density at the carbon leading to a faster attack by the nucleophile.
Oxidation of one mole of glycerol with periodic acid gives (a) 1 mole each of methanol, methanal and methanoic acid. (b) 1 mole of methanal and 2 moles of methanoic acid. (c) 1 mole of methanoic acid and 2 moles of methanal. (d) three moles of methanal.
The most useful reagent to distinguish ethanol from propan-1-ol is (a) \(\mathrm{HCl}\) and \(\mathrm{ZnCl}_{2}\) (b) \(\mathrm{I}_{2}\) and \(\mathrm{NaOH}\) (c) Cu at \(570 \mathrm{~K}\) (d) \(\mathrm{KMnO}_{4}\)
Which of the following is the correct order of ease of displacement of groups in substitution reactions? (a) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{3}^{-}>\mathrm{CH}_{3} \mathrm{COO}^{-}>\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}\) (b) \(\mathrm{CH}_{3} \mathrm{COO}^{-}>\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}^{-}>\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{3}^{-}\) (c) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{3}^{-}>\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}^{-}>\mathrm{CH}_{3} \mathrm{COO}^{-}\) (d) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{O}^{-}>\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{SO}_{3}^{-}>\mathrm{CH}_{3} \mathrm{COO}^{-}\)
It is feasible to prepare tertiary butyl ethyl ether by treating ethyl bromide with sodium tertiary butoxide, rather than treating tertiary butyl bromide with sodium ethoxide because (a) sodium ethoxide will not react with t-butyl bromide. (b) the first reaction is faster and gives more yield. (c) t-butyl bromide undergoes dehydrohalogenation to give alkene in presence of sodium ethoxide. (d) t-butyl bromide undergoes rearrangement.
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