Learning Materials
Features
Discover
Chapter 4: Problem 90
The compound which gives yellow precipitate when heated with iodine and alkali is (a) propan - 1 -ol (b) methanol (c) tert-butyl alcohol (d) butan- \(2-\) ol
Over 30 million students worldwide already upgrade their learning with Vaia!
All the tools & learning materials you need for study success - in one app.
Get started for free
Chlorobenzene is less reactive than benzyl chloride towards nucleophilic substitution because (a) the carbon of \(\mathrm{C}-\mathrm{Cl}\) bond in \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{Cl}\) is sp \(^{2}\) hybridized and holds the electron pair more firmly as compared to sp \(^{3}\) carbon containing chlorine in \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{Cl}\). (b) the \(\mathrm{C}-\mathrm{Cl}\) bond in \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{Cl}\) is less polar compared to that in \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{Cl}\). (c) the C-Cl bond in \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{Cl}\) acquires partial double bond character due to resonance involving the lone pair on chlorine atom. (d) the chlorine in \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{Cl}\) is deactivating due to its high electronegativity.
The correct nucleophilicity order for \(\mathrm{S}_{\mathrm{N}} 2\) reaction in protic solvents is (a) \(\mathrm{CH}_{3} \mathrm{~S}^{-}>\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{~S}^{-}>\mathrm{I}^{-}>\mathrm{CN}^{-}>\mathrm{CH}_{3} \mathrm{O}^{-}>\mathrm{OH}^{-}\) (b) \(\mathrm{CH}_{3} \mathrm{~S}^{-}>\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{~S}^{-}>\mathrm{CN}^{-}>\mathrm{I}^{-}>\mathrm{CH}_{3} \mathrm{O}^{-}>\mathrm{OH}^{-}\) (c) \(\mathrm{CN}^{-}>\mathrm{CH}_{3} \mathrm{~S}^{-}>\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{~S}^{-}>\mathrm{OH}^{-}>\mathrm{CH}_{3} \mathrm{O}^{-}>\mathrm{I}^{-}\) (d) \(\mathrm{OH}^{-}>\mathrm{CH}_{3} \mathrm{O}^{-}>\mathrm{CN}^{-}>\mathrm{CH}_{3} \mathrm{~S}^{-}>\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{~S}^{-}>\mathrm{I}^{-}\)
Match the elements of Column I to elements of Column II. There can be single or multiple matches. Column I (a) \(\mathrm{S}_{\mathrm{N}} 1\) reaction (b) \(\mathrm{S}_{\mathrm{N}} 2\) reaction (c) El reaction (d) E2 reaction Column II (p) Carbocation (q) \(\mathrm{CH}_{3}-\mathrm{CHCl}-\mathrm{CH}_{2}-\mathrm{CH}_{3}+\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{O}^{-} \stackrel{\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{OH}}{\longrightarrow}\) Major product (r) one step process (s) \(\mathrm{CH}_{3}-\mathrm{CHBr}-\mathrm{CH}_{3}+\mathrm{I}^{-} \stackrel{\text { acetoee }}{\longrightarrow}\) (t) Racemisation
Which of the following statements is correct? (a) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{~S}^{-}\) is a stronger base, but weaker nucleophile than \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{O}^{-}\). (b) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{~S}^{-}\) is a weaker base, but more nucleophilic than \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{O}^{-}\) (c) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{~S}^{-}\) is a stronger base and more nucleophilic than \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{O}^{-}\). (d) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{~S}^{-}\) is a weaker base and less nucleophilic than \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{O}^{-}\).
\(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{Br} \frac{(\text { i }) \mathrm{A}_{\mathrm{B}} \mathrm{CN}}{\left(\text { ii } \mathrm{H}_{2} / \mathrm{Ni}\right.}{\longrightarrow}\) product. The product is (a) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{NH}_{2}\) (b) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{NH}_{2}\) (c) \(\mathrm{CH}_{3} \mathrm{CH}\left(\mathrm{NH}_{2}\right) \mathrm{CH}_{3}\) (d) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{NHCH}_{3}\)
What do you think about this solution?
We value your feedback to improve our textbook solutions.
Explanations 
Textbooks 
Exams 
GCSE 
IGCSE 
AS 
A Level 
International A Level 
University Admissions Tests 
Flashcards 
Vaia AI 
Notes 
Study Plans 
Study Sets 
Find a job 
Find a degree 
Student Deals 
Magazine 
Mobile App