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Chapter 4: Problem 91

[A] \(\frac{\text { (i) } \mathrm{B}_{2} \mathrm{H}_{6} \text { /ether }}{\text { (ii) } \mathrm{H}_{2} \mathrm{O}_{2} / \mathrm{OH}^{-}}\) Isobutyl alcohol. The compound \([\mathrm{A}]\) in the above reaction is (a) But-1-ene (b) But-2-ene (c) 2 -Methyl propene (d) 2, 2-Dimethyl but \(-1\) -ene

Short Answer

Expert verified
Answer: The structure of compound A is 2-methyl propene.

Step by step solution

01

Write the structure of isobutyl alcohol

Isobutyl alcohol has the structure \(\mathrm{CH}_{3}\mathrm{CH}(\mathrm{CH}_{3})\mathrm{CH}_{2}\mathrm{OH}\).
02

Determine the corresponding alkene (Compound A)

Given that the reaction used \(\mathrm{B}_{2}\mathrm{H}_{6}\) in ether and then \(\mathrm{H}_{2}\mathrm{O}_{2}\), \(\mathrm{OH}^-\), this implies that it is an example of hydroboration-oxidation reaction, which converts an alkene to an alcohol. Knowing this, we should determine the alkene structure that would give us isobutyl alcohol after hydroboration-oxidation. Since the reaction proceeds with anti-Markovnikoff addition, we can determine that the alkene has the following structure: \(\mathrm{CH}_{3}\mathrm{CH}\mathrm{CH}_{3}\mathrm{CH}_{2}\), which is a 3-carbon alkene with a double bond between the first and second carbon atoms. This is known as 2-methyl propene.
03

Identify the correct option

Now that we know the structure of compound A, we can identify the correct option from the given choices. The correct answer is (c) 2-Methyl propene.

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