Ethane-1, 2- diol when heated with \(\mathrm{PI}_{3}\) (or excess HI) gives (a) Iodoethane (b) \(1,2-\) di iodoethane (c) 2 - Iodoethanol (d) ethene

Short Answer

Expert verified
Answer: The product formed is 1,2-diiodoethane (CH2I-CH2I).

Step by step solution

01

Identify the structure of Ethane-1, 2-diol

Ethane-1, 2-diol has the following structural formula: CH2(OH)-CH2(OH). It contains two hydroxyl groups (-OH) attached to each carbon of an ethane molecule.
02

Write the reaction of Ethane-1, 2-diol with PI3 or excess HI

When ethane-1, 2-diol reacts with PI3, the hydroxyl groups (-OH) are replaced by iodine atoms (-I). This is because the reaction between PI3 (or excess HI) and alcohols (e.g. ethane-1, 2-diol) follows the mechanism of nucleophilic substitution, in which iodine replaces the hydroxyl groups. Reaction: CH2(OH)-CH2(OH) + 2PI3 → CH2I-CH2I Similarly, when ethane-1, 2-diol reacts with excess HI, the HI provides the iodine atoms that will replace the hydroxyl groups (-OH). Reaction: CH2(OH)-CH2(OH) + 2HI → CH2I-CH2I + 2H2O
03

Identify the correct product

As shown in the reactions above, the product obtained after heating ethane-1, 2-diol with PI3 or excess HI is CH2I-CH2I, which is the 1,2-diiodoethane. Thus, the correct answer is (b) 1,2-diiodoethane.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Nucleophilic Substitution Reactions
In organic chemistry, nucleophilic substitution reactions are fundamental processes where an electron-rich nucleophile selectively bonds with or attacks the positive charge of an atom to replace a leaving group. This can often be seen in the reactions of alcohols with phosphorus trihalides or halogen acids, like in our example of ethane-1,2-diol and PI3 or excess HI.

When the nucleophile, in this case iodine from PI3 or HI, approaches the electrophilic carbon (the carbon bonded to the leaving group -OH), the hydroxyl groups are displaced. This displacement, due to the carbon's partial positive charge, allows the nucleophile to bond, forming a new product. Students should note that the nucleophilicity of a molecule is influenced by several factors, including the molecule's charge, the solvent, the electronegativity of the atom, and the steric hindrance.

Understanding the mechanism of nucleophilic substitution helps in predicting the outcome of reactions involving halogens and alcohols. A classic example of such a reaction is the conversion of ethane-1,2-diol to 1,2-diiodoethane.
Ethane-1,2-diol
Ethane-1,2-diol, commonly known as ethylene glycol, is an organic compound widely used as an antifreeze in cooling and heating systems due to its low freezing point. Structurally, it is composed of a two-carbon chain with hydroxyl groups (-OH) attached to each carbon, denoted chemically as CH2(OH)-CH2(OH).

It's pivotal for students to visualize the molecule and understand how the hydroxyl groups' positioning can affect the molecule’s chemical reactivity. In the context of nucleophilic substitution reactions, the hydroxyl groups in ethane-1,2-diol are prone to substitution, making it a perfect candidate for demonstrating how alcohols react with halogenating agents such as PI3 or excess HI to form halogenated products.
Halogenation of Alcohols
Halogenation refers to the process where one or more halogen atoms are introduced into a molecule, often by replacing certain groups such as hydroxyl (-OH) in alcohols. This chemical transformation is important in creating various compounds in organic synthesis and industrial applications. With alcohols like ethane-1,2-diol, halogenation typically occurs via a nucleophilic substitution reaction.

The alcohol's hydroxyl group makes it susceptible to reaction with halogenating agents. When reacting with PI3 or excess HI, a clear example of this reactivity is observed. The halogenation of alcohols can lead to the formation of alkyl halides, which have a wide range of uses, including serving as intermediates in the manufacture of other organic compounds. In the provided exercise, ethane-1,2-diol is converted into 1,2-diiodoethane, showcasing how halogenation can result in significant changes to an organic molecule's structure and properties.

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Most popular questions from this chapter

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If 4 -bromo-1-butanol is treated with sodium, a product of molecular formula \(\mathrm{C}_{4} \mathrm{H}_{8} \mathrm{O}\) is formed. Arrive at the structure and propose a mechanism.

Directions: Each question contains Statement- 1 and Statement-2 and has the following choices (a), (b), (c) and (d), out of which ONLY ONE is correct. (a) Statement- 1 is True, Statement- 2 is True; Statement- 2 is a correct explanation for Statement-1 (b) Statement- 1 is True, Statement- 2 is True; Statement- 2 is NOT a correct explanation for Statement-1 (c) Statement- 1 is True, Statement- 2 is False (d) Statement- 1 is False, Statement- 2 is True Statement 1 Nucleophilicity does not always match with basicity. and Statement 2 While nucleophilicity is more related to size, polarizability and steric factors, the basicity is the ability to abstract a proton from a substrate.

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