When calcium propanoate is distilled, the product obtained is (a) 2 -pentanone (b) 3 -pentanone (c) propanal (d) propanone

Short Answer

Expert verified
Answer: 2-pentanone

Step by step solution

01

Analyze the structure of calcium propanoate

Calcium propanoate or calcium propionate has the chemical formula Ca(C2H5COO)2. It is made up of a calcium ion (Ca2+) and two propanoate ions (C2H5COO-). The propanoate ion has the structure: CH3CH2COO- In order to determine the product obtained when distilling calcium propanoate, we need to analyze the chemical changes that occur during the distillation process.
02

Examine the distillation process

Distillation is a process that typically involves heating a liquid to form vapor, then cooling the vapor to collect the purified product. However, in the case of calcium propanoate, it undergoes a process called decarboxylation when heated. Decarboxylation is the removal of a carboxyl group (COOH) from the molecule, resulting in the release of carbon dioxide (CO2) and a new organic molecule. Note that in the case of calcium propanoate, we are working with carboxylate ions (COO-), but the principle of decarboxylation remains the same.
03

Determine the possible products from the decarboxylation of calcium propanoate

When calcium propanoate undergoes decarboxylation, the carboxylate ion (COO-) is lost, and two propanoate ions (C2H5COO-) combine to form a new organic molecule. Let's analyze each of the given options: (a) 2-pentanone has the structure CH3CH2CH2COCH3. This molecule can be formed by joining two propanoate ions at the carbonyl group after losing the carboxylate ions. It's a possible product of the decarboxylation process. (b) 3-pentanone has the structure CH3CH2COCH2CH3. This molecule cannot be formed from the distillation of calcium propanoate as it would require a different distribution of carbons and a loss of a different group. (c) Propanal has the structure CH3CH2CHO. This molecule cannot be formed from the distillation of calcium propanoate as it would require the addition of an aldehyde group instead of removing a carboxylate group. (d) Propanone has the structure CH3COCH3. This molecule also cannot be formed from the distillation of calcium propanoate as it would require a different distribution of carbons.
04

Choose the correct answer

Based on the analysis done in Step 3, the product obtained when calcium propanoate is distilled is 2-pentanone. Therefore, the correct answer is option (a) 2-pentanone.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The acylating species in the Friedel-Crafts acylation of benzene to give acetophenone is (a) \(\mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{O}^{\odot}\) (b) \(\mathrm{AlCl}_{4}\) (c) \(\mathrm{CH}_{3}-\stackrel{\oplus}{\mathrm{C}}=\ddot{\mathrm{O}}\) (d) \(\mathrm{CH}_{3}^{-\mathrm{C} \mathrm{C} \mathrm{Cl}}-\mathrm{O}-\mathrm{AlCl}\)

The reagent that can be employed for the conversion \(\mathrm{H}_{2} \mathrm{C}=\mathrm{CH}-\mathrm{CH}_{2} \mathrm{OH} \rightarrow \mathrm{H}_{2} \mathrm{C}=\mathrm{CH}-\mathrm{CHO}\) is (a) acidified \(\mathrm{KMnO}_{4}\) (b) alkaline \(\mathrm{KMnO}_{4}\) (c) \(\mathrm{MnO}_{2}\) (d) \(\mathrm{Ag}_{2} \mathrm{O}\) moist

\(\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}_{2}+\mathrm{CO}+\mathrm{H}_{2} \mathrm{O} \frac{\mathrm{H}_{2} \mathrm{FO}_{+}, 573-673 \mathrm{~K}}{\text { Presure }}{\longrightarrow} \mathrm{P}\) The product \(\mathrm{P}\) in the above reaction is (a) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{COOH}\) (b) \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CHCOOH}\) (c) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CHO}\) (d) \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CH} \mathrm{CHO}\)

\(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{3} \stackrel{(\mathrm{A})}{\longrightarrow} \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{Br} \stackrel{(\mathrm{B})}{\longrightarrow} \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{CN} \stackrel{(\mathrm{C})}{\longrightarrow} \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{COOH}\) \((\mathrm{A}),(\mathrm{b})\) and \((\mathrm{c})\) are respectively, (a) \(\mathrm{NBS}, \mathrm{KCN}\) and \(\mathrm{H}_{\mathrm{y}} \mathrm{O}^{+}\) (b) \(\mathrm{Br}_{2} / \mathrm{Fe}, \mathrm{KCN}\) and \(\mathrm{H}_{3} \mathrm{O}^{+}\) (c) \(\mathrm{Br}_{2} / \mathrm{Fe}, \mathrm{HCN}\) and \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\) (d) \(\mathrm{NBS}, \mathrm{AgCN}\) and \(\mathrm{H}_{3} \mathrm{O}^{+}\)

The products of oxidation of 2 -pentanone with concentrated nitric acid are (a) propanoic acid and ethanoic acid (b) butanoic acid and methanoic acid (c) propanoic acid and methanoic acid (d) 2 -methyl propanoic acid and methanoic acid

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free