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Chapter 5: Problem 131

Identify the product (b) in the following sequence of reactions. \(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CHO} \stackrel{\mathrm{H}_{2} \mathrm{NOH}}{\longrightarrow}(\mathrm{A}) \stackrel{\mathrm{P}_{+} \mathrm{O}_{\mathfrak{l}}}{\longrightarrow}(\mathrm{B})\) (a) \(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CN}\) (b) \(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}=\mathrm{NH}\) (c) \(\mathrm{CH}_{2}=\mathrm{CH}-\mathrm{CH}=\mathrm{NOH}\) (d) \(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{NH}_{2}\)

Short Answer

Expert verified
Question: Identify the structure of product B in the given reaction sequence: \(CH_3-CH_2-CHO\) reacts with \(H_2NOH\) to form product A, which then reacts with \(P_+O_l\) to form product B. The possible options for product B are: (a) \(CH_3-CH_2-CN\) (b) \(CH_3-CH_2-COOH\) (c) \(CH_3-CHO\) (d) \(\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{NH}_2\) Answer: (a) \(CH_3-CH_2-CN\)

Step by step solution

01

Identify Intermediate Product (A)

The first reaction involves the conversion of an aldehyde (\(-CHO\)) to another functional group using \(H_2NOH\). This reagent is typically used to convert the carbonyl group of an aldehyde into an imine. Thus, the intermediate product (A) after this reaction will have the following structure: \(CH_3-CH_2-CH=NH\).
02

Identify Product (B)

The second reaction involves the conversion of intermediate product (A) using \(P_+O_l\). This reagent typically oxidizes imines to nitriles, which contain the -\(CN\) functional group. Considering the structure of the intermediate product (A), the final product (B) will have the following structure: \(CH_3-CH_2-CN\). Comparing this result with the given options, option (a) is the correct answer: (a) \(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CN}\)

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Most popular questions from this chapter

Which of the following halides will not give good yield of the corresponding acid by the conversion to cyanide, followed by hydrolysis? (a) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{Br}\) (b) \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{CBr}\) (c) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{Br}\) (d) CC1CCCCC1

Which carbonyl compound among the following is most reactive towards nucleophilic addition? (a) CCC(=O)CC (b) CC(=O)CCl (c) CC(=O)CCCl (d)

O=C1C=CCCC1Cl The IUPAC name of (a) 2 -chlorocyclohex-5-en-1-one (b) 6 -chlorocyclohex-2-en-1-one (c) 4 -chloro-3-oxocyclohex-l-ene (d) 1 -chloro-2-oxocyclohex-3-ene

Directions: Each question contains Statement- 1 and Statement- 2 and has the following choices (a), (b), (c) and (d), out of which ONLY ONE is correct. (a) Statement- 1 is True, Statement- 2 is True; Statement- 2 is a correct explanation for Statement- 1 (b) Statement- 1 is True, Statement- 2 is True; Statement- 2 is NOT a correct explanation for Statement- 1 (c) Statement- 1 is True, Statement- 2 is False (d) Statement- 1 is False, Statement- 2 is True Statement 1 Formic acid produces a white precipitate with \(\mathrm{HgCl}_{2}\). and Statement 2 Mercuric salt of formic acid is insoluble and therefore gets precipitated.

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