Statement 1 o-hydroxy benzene sulphonic acid on heating to \(373 \mathrm{~K}\) changes to \(\mathrm{p}\) -hydroxy benzene sulphonic acid and Statement 2 Sulphonation of phenol is a reversible process.

In this step, we need to identify the starting compounds and the products in the given statements. o-hydroxy benzene sulphonic acid, which is commonly known as ortho-sulphophenol, will change to p-hydroxy benzene sulphonic acid, commonly known as para-sulphophenol, upon heating. The given statements suggest that sulphonation of phenol is a reversible process, which means this reaction can occur in both the forward and reverse directions.

First, we need to write the balanced chemical equation for the sulphonation of phenol: C6H5OH (Phenol) + H2SO4 (Sulfuric Acid) \(\overset{373 K}{\longleftrightarrow}\) C6H4(OH)SO3H (ortho-sulphophenol) + H2O (Water) Notice that we used a double arrow (↔) to represent the reversible reaction, where the reaction is occurring in both the forward and reverse directions.

Sulphonation of phenol is a reversible process that takes place in the presence of sulfuric acid. In this reaction, the -OH group present at the ortho position of the phenol reacts with the H2SO4, and results in the formation of the -SO3H group at either the ortho or para position. Heating the o-hydroxy benzene sulphonic acid to 373 K shifts the equilibrium towards the formation of p-hydroxy benzene sulphonic acid, which is the major product in the reaction. #Conclusion# Both statements are true. o-hydroxy benzene sulphonic acid (ortho-sulphophenol) changes to p-hydroxy benzene sulphonic acid (para-sulphophenol) on heating to 373 K, and sulphonation of phenol is a reversible process that involves sulfuric acid and phenol reacting to form ortho- and para-sulphophenol.