Wolff-Kishner reduction of benzophenone gives (a) benzene (b) toluene (c) diphenylmethane (d) ethylbenzene

Short Answer

Expert verified
Answer: The product formed when benzophenone undergoes Wolff-Kishner reduction is diphenylmethane.

Step by step solution

01

Identify the starting compound

The starting compound is benzophenone, which has a carbonyl group and two phenyl groups, as shown below: Benzophenone: C6H5C(O)C6H5
02

Understand the Wolff-Kishner reduction reaction mechanism

The Wolff-Kishner reduction involves treating the carbonyl compound with hydrazine (N2H4) and a strong base. This reaction converts the carbonyl group into a methylene group (-CH2-). The overall reaction mechanism is as follows: 1. Formation of the hydrazone: The carbonyl compound reacts with hydrazine to form a hydrazone derivative. 2. Formation of the nitrogen anion: The strong base deprotonates the hydrazone, which then eliminates the dinitrogen (N2) molecule to form the nitrogen anion. 3. Formation of the final reduced product: The nitrogen anion acts as a nucleophile and attacks one of the phenyl groups, resulting in the formation of a methylene group in between the two phenyl groups.
03

Determine the product based on the reaction mechanism

Applying the Wolff-Kishner reaction mechanism to benzophenone, the carbonyl group is reduced to a methylene group and the molecule becomes: Diphenylmethane: C6H5CH2C6H5 Now, we can match this product with the given options.
04

Choose the correct option

Comparing the product obtained in step 3 with the given options, we find that the correct option is: (c) diphenylmethane

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