Malonic acid on heating at \(430 \mathrm{~K}\) yields (a) formic acid (b) succinic acid (c) acetic acid (d) lactic acid

Short Answer

Expert verified
Answer: (a) Formic acid (HCOOH)

Step by step solution

01

Identifying Malonic Acid

Malonic acid (C3H4O4) is a dicarboxylic acid, which means it contains two carboxyl functional groups (-COOH). Its structure is HOOC-CH2-COOH.
02

Malonic Acid Decomposition

Upon heating, malonic acid undergoes a decarboxylation reaction in which one of the carboxyl groups (-COOH) is lost as carbon dioxide gas (CO2), and a new compound is formed. The reaction is as follows: $$ \mathrm{HOOC-CH_2-COOH \xrightarrow{\Delta} RCOOH + CO_2} $$ where RCOOH denotes the remaining acid after the reaction.
03

Identifying the Product Formed

Now, we need to determine which of the given options is formed upon heating malonic acid. Considering the decarboxylation reaction, the possible products for the remaining acid (RCOOH) are: (a) formic acid (HCOOH) (b) succinic acid (HOOC-CH2-CH2-COOH) (c) acetic acid (CH3COOH) (d) lactic acid (CH3CHOHCOOH) From the given options, we can see that option (a) formic acid is the only option that satisfies the reaction requirements, as it involves losing only one carboxyl group.
04

Final Answer

Based on the decarboxylation reaction, malonic acid (HOOC-CH2-COOH) on heating at \(430 \mathrm{~K}\) yields formic acid (HCOOH). Therefore, the correct answer is (a) formic acid.

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Most popular questions from this chapter

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