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Chapter 5: Problem 8

What is the important organic product formed by the electrolysis of (i) potassium succinate (ii) potassium maleate

Short Answer

Expert verified
Answer: The major organic products formed during the electrolysis of potassium succinate and potassium maleate are ethylene (C₂H₄) and acetylene (C₂H₂), respectively.

Step by step solution

01

Identify the half-cell reactions for potassium succinate

Begin by drawing the structure of succinate anion and identifying the oxidation and reduction half-reactions. Potassium succinate forms succinate ions (C4H4O4^2-) when dissolved in water: Oxidation half-cell reaction (anode): The two carbons bonded to the same oxygen are most likely to be oxidized, which will lead to the formation of a double bond between these two carbons. Reduction half-cell reaction (cathode): Since water is present, it will undergo reduction to form hydrogen gas (H₂) and hydroxide ion (OH⁻).
02

Predict the major organic product for potassium succinate

Using the half-cell reactions identified in Step 1, we can predict the major organic product. The two carbons bonded to the same oxygen in the succinate ion will form a double bond and produce ethylene (\(C_2H_4\)). The hydrogen gas and hydroxide ions will also be formed simultaneously during the electrolysis. Major organic product: Ethylene (\(C_2H_4\))
03

Identify the half-cell reactions for potassium maleate

Now, let's perform the same analysis for potassium maleate. Potassium maleate forms maleate ions (C4H2O4^2-) when dissolved in water: Oxidation half-cell reaction (anode): The carbons in the carbon-carbon double bond can be further oxidized (since they are already partially oxidized), leading to the formation of a carbon-carbon triple bond. Reduction half-cell reaction (cathode): Just like in the case of potassium succinate, water will be reduced to form hydrogen gas (H₂) and hydroxide ion (OH⁻).
04

Predict the major organic product for potassium maleate

Based on the half-cell reactions identified in Step 3, the major organic product can be predicted. The carbon-carbon double bond in maleate ions will form a carbon-carbon triple bond, resulting in the formation of acetylene (\(C_2H_2\)). The hydrogen gas and hydroxide ions will also be formed during electrolysis. Major organic product: Acetylene (\(C_2H_2\)) In summary, the major organic products formed during the electrolysis of potassium succinate and potassium maleate are ethylene (\(C_2H_4\)) and acetylene (\(C_2H_2\)), respectively.

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Most popular questions from this chapter

Write the steps involved in the following conversions? (a) Benzaldehyde to benzophenone (b) Benzaldehyde to 3 -phenylpropan-1-ol (c) Benzene to 2-phenyl ethanoic acid

Directions: Each question contains Statement- 1 and Statement-2 and has the following choices (a), (b), (c) and (d), out of which ONLY ONE is correct. (a) Statement- 1 is True, Statement- 2 is True; Statement- 2 is a correct explanation for Statement- 1 (b) Statement- 1 is True, Statement- 2 is True; Statement- 2 is NOT a correct explanation for Statement-1 (c) Statement- 1 is True, Statement- 2 is False (d) Statement- 1 is False, Statement- 2 is True Statement 1 Eventhough carboxylic acids contain a \(>C=O\) group, they do not give the characteristic reaction of carbonyl compounds. and Statement 2 The electrophilicity of carbonyl carbon is less in carboxylic acids due to resonance.

The IUPAC name of is CCC(C=O)CC(C)C (a) 2 -ethyl-4-methylpentanal (b) 4 -methyl 2 -ethylpentanal (c) 2 -methylhexanal (d) 2 -ethylhexanal

A compound, which is known as oil of bitter almonds is (a) acetaldehyde (b) acetone (c) acetophenone (d) benzaldehyde

Which of the following statements relating to the derivatives of carboxylic acids are correct? [R]C(N)=O (a) An amide \(\mathrm{R}-\mathrm{C}_{-\mathrm{N} \mathrm{H}}\) answers all the tests for a primary amine. (b) Among the carboxylic acid derivatives, acid chloride is the most reactive. Aldehydes, Ketones and Carboxylic Acids \(5.57\) (c) Carboxylic acid can be converted to an ester by reacting with alcohol in the presence of a base. (d) Benzoic acid can be converted to methyl benzoate by using diazomethane.
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