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Chapter 5: Problem 86

Dry distillation of calcium benzoate will give (a) acetophenone (b) benzophenone (c) benzaldehyde (d) 2-phenyl ethanol

Short Answer

Expert verified
Answer: (c) Benzaldehyde

Step by step solution

01

1. Identify the reactant

Calcium benzoate is the reactant in this exercise. Its molecular formula is Ca(C6H5COO)2.
02

2. Write the dry distillation reaction for calcium benzoate

During dry distillation, calcium benzoate is heated in the absence of air, leading to the formation of a product. The general reaction is: Ca(C6H5COO)2 -> Product + Calcium Carbonate (CaCO3)
03

3. Identify the product formed

When calcium benzoate undergoes dry distillation, the benzoate group is lost, and the remaining part of the molecule rearranges to form the product. In this case, calcium benzoate will form benzaldehyde (C6H5CHO) along with calcium carbonate (CaCO3): Ca(C6H5COO)2 -> C6H5CHO + CaCO3 Comparing the formed product with the given options, we can see that the correct answer is (c) benzaldehyde.

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Most popular questions from this chapter

Identify the correct statements among the following. (a) Formaldehyde can react with both \(-\mathrm{NH}_{2}\) groups in semicarbazide. (b) In mixed Cannizzaro reaction involving HCHO, it is always the intermediate formed from HCHO which transfers its hydride to the other aldehyde. (c) Benzaldehyde reduces both Tollens' reagent and Fehling's solution. (d) In Fehling's solution, Cu(II) ions are kept in soluble form of a complex in alkaline medium.

CC(Cl)(Cl)Cl (b) O=[N+]([O-]… # Which of the following is obtained when 4-chlorobenzene sulphonic acid is treated with excess sodium acetate? (a) N#CC(Cl)(Cl)Cl (b) O=[N+]([O-])c1ccc(Cl)cc1 \(+\mathrm{CH}_{3} \mathrm{COOH}\) COC(=O)c1ccc(O)cc1 \(\mathrm{NaOH}\) (c) O=C(O)Cc1ccc(Cl)cc1 (d)

Identify the true statements about methanoic acid. (a) It is formed by heating glycerol with oxalic acid to about \(373 \mathrm{~K}\). (b) It gives formyl chloride when treated with \(\mathrm{PCl}_{5^{*}}\) (c) It is a stronger acid than benzoic acid. (d) It gives carbon monoxide on heating with con. \(\mathrm{H}_{2} \mathrm{SO}_{4}\).

The acylating species in the Friedel-Crafts acylation of benzene to give acetophenone is (a) \(\mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{O}^{\odot}\) (b) \(\mathrm{AlCl}_{4}\) (c) \(\mathrm{CH}_{3}-\stackrel{\oplus}{\mathrm{C}}=\ddot{\mathrm{O}}\) (d) \(\mathrm{CH}_{3}^{-\mathrm{C} \mathrm{C} \mathrm{Cl}}-\mathrm{O}-\mathrm{AlCl}\)

The reagent that can be used to distinguish between pentan-2-one and pentan-3-one is (a) \(\mathrm{Zn}-\mathrm{Hg} / \mathrm{HCl}\) (b) \(\mathrm{SeO}_{2}\) (c) \(\mathrm{I}_{2} / \mathrm{NaOH}\) (d) \(\mathrm{KMnO}_{4} / \mathrm{H}_{2} \mathrm{SO}_{4}\)
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