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Chapter 5: Problem 91

\(\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}_{2}+\mathrm{CO}+\mathrm{H}_{2} \mathrm{O} \frac{\mathrm{H}_{2} \mathrm{FO}_{+}, 573-673 \mathrm{~K}}{\text { Presure }}{\longrightarrow} \mathrm{P}\) The product \(\mathrm{P}\) in the above reaction is (a) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{COOH}\) (b) \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CHCOOH}\) (c) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CHO}\) (d) \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CH} \mathrm{CHO}\)

Short Answer

Expert verified
Answer: The product P is (c) \(\mathrm{CH}_{3}\mathrm{CH}_{2}\mathrm{CH}_{2}\mathrm{CHO}\).

Step by step solution

01

Identify the type of reaction

The reactants include an alkene(\(\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}_{2}\)), carbon monoxide (CO), and water (H2O), and the reaction is catalyzed by H2FO+. This is a hydroformylation reaction, which involves the addition of a formyl group (CHO) and a hydrogen atom across a carbon-carbon double bond.
02

Write out the general formula for hydroformylation

In hydroformylation, we will add a formyl group (CHO) and a hydrogen atom (H) across the carbon-carbon double bond of the alkene. Based on this, the general formula of the product (R- represents the existing alkyl group) will be R-CH2-CH2-CHO.
03

Apply the general formula to the given alkene

Our given alkene is propene (\(\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}_{2}\)), so we just need to apply the general formula to find the product. By adding the formyl group and the hydrogen atom across the double bond, we get: \(\mathrm{CH}_{3}\mathrm{CH}_{2}\mathrm{CH}_{2}\mathrm{CHO}\)
04

Match the product with one of the given options

Compare the product found in step 3 with the four given options, and you will see that the correct product is: (c) \(\mathrm{CH}_{3}\mathrm{CH}_{2}\mathrm{CH}_{2}\mathrm{CHO}\)

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Most popular questions from this chapter

\(\mathrm{H}_{2} \mathrm{C}=\mathrm{CH}-\mathrm{C}^{\mathrm{O}} \sum_{\mathrm{H}}^{\mathrm{CH}_{3} \mathrm{OH}}{\mathrm{dryHCl}}(\mathrm{A}) \stackrel{\mathrm{dil.KMnO}_{4}}{\longrightarrow}(\mathrm{B}) \stackrel{\mathrm{dil} \cdot \mathrm{HCl}}{\longrightarrow}(\mathrm{C})\) The structure of (C) is (a) \(\mathrm{H}_{2} \mathrm{C}=\mathrm{CHCH}_{2} \mathrm{OH}\) (b) \(\mathrm{HOCH}_{2}-\mathrm{CHOH}-\mathrm{CHO}\) (c) \(\mathrm{OHC}-\mathrm{CH}_{2}-\mathrm{COOH}\) (d) \(\mathrm{CH}_{2}=\mathrm{CH}-\mathrm{COOH}\)

Which of the following pairs will give effervescence with aqueous sodium hydrogen carbonate solution? (a) \(\mathrm{CH}_{3} \mathrm{COCl}\) and \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CO}\) (b) \(\mathrm{CH}_{3} \mathrm{CONH}_{2}\) and \(\left(\mathrm{CH}_{3} \mathrm{CO}\right)_{2} \mathrm{O}\) (c) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}\) and \(\mathrm{CH}_{3} \mathrm{COOCH}_{3}\) (d) \(\mathrm{CH}_{3} \mathrm{COCl}\) and \(\left(\mathrm{CH}_{3} \mathrm{CO}\right)_{2} \mathrm{O}\)

CC(Cl)(Cl)Cl (b) O=[N+]([O-]… # Which of the following is obtained when 4-chlorobenzene sulphonic acid is treated with excess sodium acetate? (a) N#CC(Cl)(Cl)Cl (b) O=[N+]([O-])c1ccc(Cl)cc1 \(+\mathrm{CH}_{3} \mathrm{COOH}\) COC(=O)c1ccc(O)cc1 \(\mathrm{NaOH}\) (c) O=C(O)Cc1ccc(Cl)cc1 (d)

The reagent that can be used for the conversion of \(\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CHCHO}\) to \(\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CHCOOH}\) is (a) Alkaline \(\mathrm{KMnO}_{4}\) (b) \(\mathrm{Zn}(\mathrm{Hg}) / \mathrm{HCl}\) (c) \(\mathrm{PCC} / \mathrm{CH}_{2} \mathrm{Cl}_{2}\) (d) Tollens' reagent

Terephthalic acid is obtained by the oxidation of ( \(\mathrm{X}\) ) with acidified \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{r^{*}}(\mathrm{X})\) is (a) ortho xylene (b) meta xylene (c) para xylene (d) ethylbenzene
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