Account for the following observations (i) Acetonitrile is preferred as a solvent for many organic reactions. (ii) Benzamide is not soluble in hydrochloric acid, whereas aniline is soluble, though both contain the \(-\mathrm{NH}_{2}\) group.

Short Answer

Expert verified
Answer: Acetonitrile is a preferred solvent for many organic reactions due to its polar aprotic nature, ability to dissolve various organic compounds, and stabilization of reaction transition states. Benzamide is insoluble in hydrochloric acid because its amide functionality with a carbonyl group prevents it from reacting with the acid. In contrast, aniline is soluble due to its primary amine functionality allowing it to form a soluble salt with the acid.

Step by step solution

01

Examine properties of Acetonitrile

Acetonitrile (\(\mathrm{CH}_{3}\mathrm{CN}\)) is a widely used polar aprotic solvent. Polar aprotic solvents have a significant dipole moment and lack acidic protons available for hydrogen bonding. Acetonitrile has low toxicity, low miscibility with water, and the ability to dissolve a wide range of organic solutes.
02

Understand why Acetonitrile is a preferred solvent

Due to its polar aprotic nature, acetonitrile can dissolve a wide variety of organic compounds. Furthermore, it can stabilize the transition states of reactions, reducing the activation energy required for the reaction to occur. Its low boiling point makes it easy to remove after the reaction has taken place. Overall, its properties make it an excellent solvent choice for many organic reactions.
03

Examine the structure of Benzamide and Aniline

Benzamide is an amide with the chemical formula \(\mathrm{C}_{6}\mathrm{H}_{5}\mathrm{CONH}_{2}\), while aniline is an amine with the chemical formula \(\mathrm{C}_{6}\mathrm{H}_{5}\mathrm{NH}_{2}\). Despite both containing the \(-\mathrm{NH}_{2}\) group, benzamide has a carbonyl group (\(-\mathrm{C=O}\)) in its structure, which plays a crucial role in its difference in solubility compared to aniline.
04

Compare solubility in hydrochloric acid

When placed in hydrochloric acid (\(\mathrm{HCl}\)), aniline reacts by donating a pair of electrons from the nitrogen in the \(-\mathrm{NH}_{2}\) group, forming a salt, which makes it soluble in the acidic solution: $$\mathrm{C}_{6}\mathrm{H}_{5}\mathrm{NH}_{2} + \mathrm{HCl} \rightarrow \mathrm{C}_{6}\mathrm{H}_{5}\mathrm{NH}_{3}^{+}\mathrm{Cl}^{-}$$ However, benzamide does not react with hydrochloric acid due to its amide functionality. The carbonyl group (\(-\mathrm{C=O}\)) has a resonance structure that delocalizes the lone pair of electrons on the nitrogen, making it less available for reacting with \(\mathrm{HCl}\). Without any ionic interaction or formation, benzamide remains insoluble in hydrochloric acid.
05

Conclusion

In conclusion, acetonitrile is preferred as a solvent for many organic reactions due to its polar aprotic nature and ability to dissolve a wide range of organic compounds while stabilizing the reaction's transition states. Benzamide is not soluble in hydrochloric acid because its amide functionality prevents it from reacting with the acid, while aniline forms a soluble salt with the acid due to its primary amine functionality.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free