Reduction of benzenediazonium chloride with zinc and hydrochloric acid gives (a) aniline (b) azobenzene (c) phenyl hydrazine (d) benzene

Short Answer

Expert verified
Answer: Benzene (C_6H_6)

Step by step solution

01

Identify the reactants and the reducing agent

In this reaction, benzenediazonium chloride is the reactant that will be reduced and zinc (Zn) with hydrochloric acid (HCl) will act as the reducing agent.
02

Understand the reduction of benzenediazonium chloride

When benzenediazonium chloride is reacted with a reducing agent like zinc and hydrochloric acid, it undergoes reduction. The nitrogen-nitrogen bond in the diazonium compound is broken and replaced by a hydrogen atom.
03

Write the balanced chemical reaction

The balanced chemical reaction for the reduction of benzenediazonium chloride with zinc and hydrochloric acid can be written as follows: C_6H_5N_2^+Cl^- + Zn + 2HCl -> C_6H_6 + N_2 + ZnCl_2 + H_2
04

Identify the product formed

From the above balanced chemical equation, it can be observed that the product formed after the reduction of benzenediazonium chloride is benzene (C_6H_6).
05

Choose the correct answer

Based on the product formed, the correct answer is: (d) benzene

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