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Chapter 6: Problem 144

Which of the following compounds on oxidation with acidified dichromate gives p-benzoquinone?

Short Answer

Expert verified
Short Answer: p-Benzoquinone is an organic compound that is derived from benzene, where the two central adjacent carbon atoms are double bonded to oxygen atoms. To identify a compound that could form p-benzoquinone when oxidized, one must search for a compound where two carbon atoms have single bonds to hydrogen atoms that can be converted into double bonds with oxygen atoms when oxidized. Since the given compounds are not provided in this prompt, for a detailed answer, compare the provided compounds using this principle. The applicable compound will be the one which, when oxidized with acidified dichromate, turns into p-benzoquinone.

Step by step solution

01

Understand p-benzoquinone

p-Benzoquinone, also known as 1,4-benzoquinone, is an organic compound with the formula C6H4O2. Structurally, it is a derivative of benzene, with the two central adjacent carbon atoms double bonded to oxygen atoms. The remaining carbon atoms of the benzene ring are connected to hydrogen atoms.
02

Write the given compounds

Let's write down the given compounds to compare them and find the one that can be oxidized to p-benzoquinone. Let's denote them as Compound 1, Compound 2, and so on.
03

Identify the compound that can be oxidized to form p-benzoquinone

To form p-benzoquinone, we need a compound that has two carbon atoms with single bonds to hydrogen atoms, which can be converted into double bonds with oxygen atoms when oxidized. Compare the given compounds and look for the one with the required structure, keeping in mind that only the carbon atoms in the benzene ring will be involved in the oxidation process to form p-benzoquinone. Once you identify the correct compound, it will be the one that, when oxidized with acidified dichromate, produces p-benzoquinone.

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Most popular questions from this chapter

Which of the following can be used to get a diazonium fluoroborate? (a) \(\mathrm{p}\) -toluidine (b) Glycine (c) Benzylamine (d) Cyclohexylamine

Maximum number of tetrapeptides that can be prepared from the 10 essential amino acids is (a) 10,000 (b) 5000 (c) 2500 (d) 15000

The reactions that can be used to prepare benzylamine are (a) Reduction of benzamide with \(\mathrm{H}_{2} / \mathrm{Pd}\). (b) Reduction of benzenecarbonitrile with \(\mathrm{SnCl}_{2} / \mathrm{HCl}\). (c) Reaction of potassium phthalimide with benzylbromide followed by hydrolysis. (d) reaction of benzoyl chloride with ammonia.

Aniline can be prepared from nitrobenzene by treating it with \(\mathrm{Zn}\) and conc. HCl. If an alkali like \(\mathrm{NaOH}\) is used instead of conc. HCl, azobenzene is formed. How can aniline be prepared after this stage? (a) oxidizing with Caro's acid (b) Reduction under acidic conditions (c) Reduction with HI and red phosphorus (d) Heating the mixture.

The hybridization of nitrogen in aniline is (a) \(s p\) (b) \(\mathrm{sp}^{2}\) (c) \(\mathrm{sp}^{3}\) (d) \(\mathrm{sp}^{3} \mathrm{~d}\)
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