Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 7: Problem 105

Explain the products obtained when (i) Fructose is treated with excess phenyl hydrazine (ii) Glucose is heated with concentrated hydrochloric acid (iii) Glucosazone is hydrolysed with dilute hydrochloric acid

Short Answer

Expert verified
Answer: (i) Fructosazone (ii) 5-(hydroxymethyl)furfural (iii) Glucose and phenyl hydrazine

Step by step solution

01

(Reaction 1: Fructose with Phenyl Hydrazine)

We are given that fructose is treated with excess phenyl hydrazine. When fructose reacts with phenyl hydrazine, it forms fructose phenylhydrazone by losing water molecules and eliminates the carbonyl group. If excess phenyl hydrazine is present, fructose phenylhydrazone further undergoes reaction to form osazone. The product of this reaction is called fructosazone.
02

(Reaction 2: Glucose with Concentrated Hydrochloric Acid)

In this reaction, we heat glucose with concentrated hydrochloric acid. The concentrated hydrochloric acid acts as a dehydrating agent and converts glucose into a five-membered ring compound called 5-(hydroxymethyl)furfural. This is because concentrated hydrochloric acid helps in the dehydration and rearrangement of glucose.
03

(Reaction 3: Glucosazone with Dilute Hydrochloric Acid)

In the third reaction, glucosazone is hydrolyzed with dilute hydrochloric acid. When glucosazone undergoes hydrolysis, it decomposes to form glucose and phenyl hydrazine. This is because the bond between the glucose moiety and the phenyl hydrazine moiety in glucosazone breaks due to the presence of dilute hydrochloric acid which acts as an acid catalyst. To summarize: 1. When fructose is treated with excess phenyl hydrazine, fructosazone is formed. 2. When glucose is heated with concentrated hydrochloric acid, 5-(hydroxymethyl)furfural is formed. 3. When glucosazone is hydrolysed with dilute hydrochloric acid, glucose and phenyl hydrazine are formed.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

This section contains multiple choice questions. Each question has 4 choices (a), (b), (c) and (d), out of which ONLY ONE is correct. A compound containing a conjugated double bond, decolourises bromine water. On heating with \(\mathrm{I}_{2}\) and \(\mathrm{NaOH}\), a yellow precipitate is formed. If the compound contains five carbons including a methyl substituent, the compound may be (a) 3 -methyl but- 3 -en- 2 -one. (b) 3 -methyl but- 3 -enal (c) 3 -methyl but- 2 -enal (d) 2 -methyl but- 2 -enal

This section contains multiple choice questions. Each question has 4 choices (a), (b), (c) and (d), out of which ONLY ONE is correct. A compound (A) reacts with phenyl hydrazine to give a crystalline yellow precipitate. When (A) is added to a solution of rosaniline-hydrochloride decolourized by \(\mathrm{SO}_{2}\) gas, the solution remains colourless. (A) is reduced with LiAlH to give (B). (B) is a (a) phenol (b) primary alcohol (c) aromatic polyhydric alcohol (d) secondary alcohol

This section contains multiple choice questions. Each question has 4 choices (a), (b), (c) and (d), out of which ONLY ONE is correct. Which of the following statements about starch is false? (a) Starch is a polymer of a-D-glucose. (b) It consists of \(20 \%\) amylose and \(80 \%\) amylopectin. (c) Glycosidic linkages between glucose units are always formed only between \(\mathrm{C}_{1}\) and \(\mathrm{C}_{4}\). (d) Amylose is water soluble and amylopectin is insoluble.

This section contains multiple choice questions. Each question has 4 choices (a), (b), (c) and (d), out of which ONLY ONE is correct. When Lassaigne's solution is treated with dil.HNO, and \(\mathrm{AgNO}_{3}\), a white precipitate soluble in ammonium hydroxide shows the presence of (a) chlorine (b) bromine (c) sulphur (d) nitrogen

This section contains multiple choice questions. Each question has 4 choices (a), (b), (c) and (d), out of which ONLY ONE is correct. Which among the following is a polymer? (a) Teflon (b) Pyrene (c) acrolein (d) Freon
See all solutions

Recommended explanations on Chemistry Textbooks

Chemical Reactions

Read Explanation

Chemical Analysis

Read Explanation

Inorganic Chemistry

Read Explanation

Kinetics

Read Explanation

Physical Chemistry

Read Explanation

The Earths Atmosphere

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free