This section contains multiple choice questions. Each question has 4 choices (a), (b), (c) and (d), out of which ONLY ONE is correct. Glucose on prolonged heating with HI and red phosphorus at \(373 \mathrm{~K}\) gives (a) sorbose (b) sorbitol (c) hexane (d) hexan-1-ol

Short Answer

Expert verified
Answer: The product formed is hexane.

Step by step solution

01

Identify the properties of glucose

Glucose is a monosaccharide with the chemical formula \(C_6H_{12}O_6\). It has an aldehyde functional group at carbon 1 and five hydroxyl (-OH) groups on the remaining carbons.
02

Identify the properties of the reagents

The reagents used in this reaction are HI (hydroiodic acid) and red phosphorus. HI is a strong acid, and red phosphorus is often used as a reducing agent.
03

Understand the reaction mechanism

When glucose reacts with HI and red phosphorus at \(373 \mathrm{~K}\), all the hydroxyl groups and the aldehyde group in glucose are reduced. The reduction of the aldehyde group results in a primary alcohol group (hexan-1-ol or hexane), and the conversion of hydroxyl groups to hydrogen atoms may result in a primary alcohol or a hydrocarbon, either hexane or hexan-1-ol.
04

Analyze the given options and determine the correct answer

Based on the possible products formed and the given options, we can eliminate options (a) and (b), as neither sorbose or sorbitol are products of the given reaction. We are now left with options (c) and (d). Since the reaction includes a reduction of the aldehyde group and all of the hydroxyl groups, the correct answer is hexane (option c).

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