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Chapter 7: Problem 50

This section contains multiple choice questions. Each question has 4 choices (a), (b), (c) and (d), out of which ONLY ONE is correct. An organic compound is treated with \(\mathrm{NaNO}_{2}\) and HCl under ice cold conditions and the resulting solution is treated with 2 -naphthol solution. A brilliant red colour indicates that the organic compound contians (a) aliphatic - \(\mathrm{NH}_{2}\) group (b) aromatic \(-\mathrm{NH}_{2}\) group (c) -CONH \(_{2}\) group (d) \(-\mathrm{NO}_{2}\) group

Short Answer

Expert verified
Answer: Aromatic amino group -NH2

Step by step solution

01

Analyzing the reaction with an aliphatic amino group

Using the knowledge of reactions, we can determine that under ice-cold conditions and in the presence of HCl and NaNO2, aliphatic amines don't give any reaction leading to the formation of a brilliant red color upon addition of 2-naphthol. Hence, option (a) is not correct.
02

Analyzing the reaction with an aromatic amino group

Under ice-cold conditions, aromatic amines initially form diazonium salts when reacted with HCl and NaNO2. These diazonium salts can further react with 2-naphthol, producing a brilliant red-colored azo dye. The appearance of a red color indicates the presence of an aromatic amino group in the organic compound. Therefore, option (b) is correct.
03

Analyzing the reaction with -CONH2 group

Amides, represented as -CONH2 group, do not exhibit any particular reaction with NaNO2 and HCl under ice-cold conditions, nor do they produce a red-colored product upon addition of 2-naphthol. As a result, option (c) is incorrect.
04

Analyzing the reaction with -NO2 group

The nitro group, represented as -NO2, does not react with NaNO2 and HCl under ice-cold conditions, nor does it produce a red-colored product upon adding 2-naphthol. That's why option (d) is incorrect.
05

Conclusion

An organic compound that produces a brilliant red color when treated with NaNO2 and HCl under ice-cold conditions, and then mixed with 2-naphthol solution, contains an aromatic -NH2 group. So, the correct answer is option (b).

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