This section contains multiple choice questions. Each question has 4 choices (a), (b), (c) and (d), out of which ONLY ONE is correct. A compound (A) reduces \(\left[\mathrm{Ag}\left(\mathrm{NH}_{3}\right)_{2}\right] \mathrm{OH}\) and \(\mathrm{HgCl}_{2}\). On warming (A) with (B) in presence of conc. \(\mathrm{H}_{2} \mathrm{SO}_{4}\) gives a product with pleasant fruity smell. When (B), containing two carbons, is heated with conc. \(\mathrm{H}_{2} \mathrm{SO}_{4}\) to \(180^{\circ} \mathrm{C},(\mathrm{C})\) is obtained. Identify correct statement regarding (C). (a) It decolourizes bromine water (b) It is oxidized to (B) by hot acidified \(\mathrm{KMnO}_{4}\) (c) It is oxidized to (A) by cold alkaline dil.KMnO (d) It is unaffected by \(\mathrm{H}_{2}\) and \(\mathrm{Pt}\)

Short Answer

Expert verified
Answer: It decolorizes bromine water.

Step by step solution

01

Understanding Reactions involving A and B

We have the following reactions: 1. A reduces [Ag(NH3)2]OH and HgCl2. 2. A reacts with B in presence of conc. H2SO4 to produce a fruity smell. From the above information: - Reducing silver and mercury salts indicates that compound A most likely has an aldehyde or a reducing sugar group. - The fruity smell of the product of the reaction between A and B in the presence of H2SO4 strongly suggests that it is an ester formation reaction.
02

Analyzing Reaction involving B and Its Structure

We are given that compound B contains two carbon atoms and its reaction with conc. H2SO4 at 180°C forms compound C. A common reaction with two carbon compounds at increased temperatures with concentrated H2SO4 is dehydration to form alkenes. Therefore, B is likely an alcohol (C2H5OH, ethanol).
03

Deduce Compound A and the product of A and B Reaction

Given that compound B is ethanol (C2H5OH), and A reacts with B to form a fruity-smelling ester, we can assume that compound A is an organic acid (e.g., CH3COOH, acetic acid). The product of this esterification reaction will be ethyl acetate (CH3COOC2H5).
04

Analyzing Compound C and Its Reactions

We know that compound C is obtained when compound B (ethanol) is heated with conc. H2SO4 at 180°C, producing an alkene. Therefore, compound C should be C2H4 (ethylene). Now, we examine each option to determine the correct statement about compound C: (a) It decolorizes bromine water: True. Alkenes like ethylene react with bromine water to form dibromoalkanes and decolorize the solution. (b) It is oxidized to (B) by hot acidified KMnO4: False. Hot acidified KMnO4 would oxidize an alkene to a ketone or an aldehyde, but not to an alcohol as in compound B. (c) It is oxidized to (A) by cold dilute alkaline KMnO4: False. Cold alkaline KMnO4 would oxidize ethylene to a diol, not an organic acid as in compound A. (d) It is unaffected by H2 and Pt: False. Ethylene (an alkene) will undergo hydrogenation to form ethane in the presence of hydrogen gas and a Pt catalyst. Based on this analysis, the correct option is: (a) It decolorizes bromine water.

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