Write the balanced equation for the following reactions. (a) Treatment of \(\mathrm{AgNO}_{3}\) with sodium thiosulphate (c) Treatment of lithium with ammonia

When silver nitrate (\(\mathrm{AgNO}_{3}\)) reacts with sodium thiosulphate (\(\mathrm{Na}_{2}\mathrm{S}_{2}\mathrm{O}_{3}\)), silver thiosulphate (\(\mathrm{Ag}_{2}\mathrm{S}_{2}\mathrm{O}_{3}\)) and sodium nitrate (\(\mathrm{NaNO}_{3}\)) are produced. The unbalanced chemical equation can be written as follows: \(\mathrm{AgNO}_{3} + \mathrm{Na}_{2}\mathrm{S}_{2}\mathrm{O}_{3} \rightarrow \mathrm{Ag}_{2}\mathrm{S}_{2}\mathrm{O}_{3} + \mathrm{NaNO}_{3}\) To balance the chemical equation, adjust the number of Ag, S, O and Na atoms on both sides of the equation. Placing a 2 in front of AgNO3 and NaNO3 will balance the silver and sodium ions: \(2\mathrm{AgNO}_{3} + \mathrm{Na}_{2}\mathrm{S}_{2}\mathrm{O}_{3} \rightarrow \mathrm{Ag}_{2}\mathrm{S}_{2}\mathrm{O}_{3} + 2\mathrm{NaNO}_{3}\)

When lithium (\(\mathrm{Li}\)) reacts with ammonia (\(\mathrm{NH}_{3}\)), lithium amide (\(\mathrm{LiNH}_{2}\)) and hydrogen (\(\mathrm{H}_{2}\)) are produced. The unbalanced chemical equation can be written as follows: \(\mathrm{Li} + \mathrm{NH}_{3} \rightarrow \mathrm{LiNH}_{2} + \mathrm{H}_{2}\) To balance the chemical equation, adjust the number of Li, N, and H atoms on both sides of the equation. Placing a 2 in front of LiNH2 will balance the lithium and nitrogen ions, and placing a 3 in front of H2 will balance the hydrogen: \(2\mathrm{Li} + \mathrm{NH}_{3} \rightarrow 2\mathrm{LiNH}_{2} + \(\frac{3}{2}\)\mathrm{H}_{2}\)