Write complete balanced equation for the reaction of the following compounds with water. (a) \(\mathrm{Li}_{2} \mathrm{O}\) (b) NaH (c) \(\mathrm{NaNH}_{2}\) (d) \(\mathrm{C}_{2} \mathrm{H}_{2}\) (e) \(\mathrm{Na}_{2} \mathrm{O}_{2}\)

Short Answer

Expert verified
(a) \(\mathrm{Li}_{2}\mathrm{O} + \mathrm{H}_{2}\mathrm{O} \rightarrow 2 \mathrm{LiOH}\)\n(b) \(\mathrm{NaH} + \mathrm{H}_{2}\mathrm{O} \rightarrow \mathrm{NaOH} + \mathrm{H}_{2}\)\n(c) \(\mathrm{NaNH}_{2} + \mathrm{H}_{2}\mathrm{O} \rightarrow \mathrm{NaOH} + \mathrm{NH}_{3}\)\n(d) \(\mathrm{C}_{2}\mathrm{H}_{2} + \mathrm{H}_{2}\mathrm{O} \rightarrow \mathrm{C}_{2}\mathrm{H}_{2} + \mathrm{H}_{2}\mathrm{O}\)\n(e) \(\mathrm{Na}_{2}\mathrm{O}_{2} + 2 \mathrm{H}_{2}\mathrm{O} \rightarrow 2 \mathrm{NaOH} + \mathrm{O}_{2}\)

Step by step solution

01

Reaction of Lithium Oxide with water

The Lithium Oxide (\(\mathrm{Li}_{2}\mathrm{O}\)) reacts with water (\(\mathrm{H}_{2}\mathrm{O}\)) to form Lithium Hydroxide (\(\mathrm{LiOH}\)):\[ \mathrm{Li}_{2}\mathrm{O} + \mathrm{H}_{2}\mathrm{O} \rightarrow 2 \mathrm{LiOH} \]
02

Reaction of Sodium Hydride with water

Sodium Hydride (NaH) reacts with water (\(\mathrm{H}_{2}\mathrm{O}\)) to form Sodium Hydroxide (\(\mathrm{NaOH}\)) and Hydrogen gas (\(\mathrm{H}_{2}\)):\[ \mathrm{NaH} + \mathrm{H}_{2}\mathrm{O} \rightarrow \mathrm{NaOH} + \mathrm{H}_{2} \]
03

Reaction of Sodium Amide with water

Sodium Amide (\(\mathrm{NaNH}_{2}\)) reacts with water (\(\mathrm{H}_{2}\mathrm{O}\)) to form Sodium Hydroxide (\(\mathrm{NaOH}\)) and Ammonia (\(\mathrm{NH}_{3}\)):\[ \mathrm{NaNH}_{2} + \mathrm{H}_{2}\mathrm{O} \rightarrow \mathrm{NaOH} + \mathrm{NH}_{3} \]
04

Reaction of Acetylene with water

Acetylene (\(\mathrm{C}_{2}\mathrm{H}_{2}\)) doesn't react with water under normal conditions, so no changes would occur:\[ \mathrm{C}_{2}\mathrm{H}_{2} + \mathrm{H}_{2}\mathrm{O} \rightarrow \mathrm{C}_{2}\mathrm{H}_{2} + \mathrm{H}_{2}\mathrm{O} \]
05

Reaction of Sodium peroxide with water

Sodium Peroxide (\(\mathrm{Na}_{2}\mathrm{O}_{2}\)) reacts with water (\(\mathrm{H}_{2}\mathrm{O}\)) to form Sodium Hydroxide (\(\mathrm{NaOH}\)) and Oxygen (\(\mathrm{O}_{2}\)):\[ \mathrm{Na}_{2}\mathrm{O}_{2} + 2 \mathrm{H}_{2}\mathrm{O} \rightarrow 2 \mathrm{NaOH} + \mathrm{O}_{2} \]

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