Complete the following reactions: (a) \(\mathrm{Be}_{2} \mathrm{C}+\mathrm{H}_{2} \mathrm{O} \longrightarrow\) (c) \(\mathrm{Mg}_{2} \mathrm{C}_{3}+\mathrm{H}_{2} \mathrm{O} \longrightarrow\) (d) \(\mathrm{Al}_{2} \mathrm{O}_{3}+\mathrm{NaOH} \longrightarrow\) (e) \(\mathrm{BeCl}_{2}+\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OC}_{2} \mathrm{H}_{5} \longrightarrow\)

Short Answer

Expert verified
The complete reactions are: (a) \(\mathrm{Be}_{2}\mathrm{C} + \mathrm{H}_{2} \mathrm{O} \longrightarrow 2 \mathrm{Be(OH)}_{2} + \mathrm{CH}_{4}\), (b) \(\mathrm{Mg}_{2}\mathrm{C}_{3} + 4 \mathrm{H}_{2} \mathrm{O} \longrightarrow 2 \mathrm{Mg(OH)}_{2} + \mathrm{C}_{2}\mathrm{H}_{2}\), (c) \(\mathrm{Al}_{2} \mathrm{O}_{3} + 2 \mathrm{NaOH} \longrightarrow 2 \mathrm{NaAlO}_{2} + \mathrm{H}_{2} \mathrm{O}\), (d) \(\mathrm{BeCl}_{2} + \mathrm{C}_{2}\mathrm{H}_{5}\mathrm{OC}_{2}\mathrm{H}_{5} \longrightarrow \mathrm{BeCl}_{2}\cdot (\mathrm{O \ C_{2} H_{5})_{2}\).

Step by step solution

01

Complete the reaction of \(\mathrm{Be}_{2}\mathrm{C}+\mathrm{H}_{2} \mathrm{O}\)

Beryllium carbide \(\mathrm{Be}_{2} \mathrm{C}\) reacts with water to form Beryllium hydroxide and Methane. The balanced reaction is written as: \( \mathrm{Be}_{2}\mathrm{C} + \mathrm{H}_{2} \mathrm{O} \longrightarrow 2 \mathrm{Be(OH)}_{2} + \mathrm{CH}_{4}\)
02

Complete the reaction of \(\mathrm{Mg}_{2}\mathrm{C}_{3}+\mathrm{H}_{2} \mathrm{O}\)

Magnesium carbide \(\mathrm{Mg}_{2}\mathrm{C}_{3}\) reacts with water to form Magnesium hydroxide and Acetylene. The balanced reaction is: \(\mathrm{Mg}_{2}\mathrm{C}_{3} + 4 \mathrm{H}_{2} \mathrm{O} \longrightarrow 2 \mathrm{Mg(OH)}_{2} + \mathrm{C}_{2}\mathrm{H}_{2}\)
03

Complete the reaction of \(\mathrm{Al}_{2} \mathrm{O}_{3}+\mathrm{NaOH}\)

Aluminium oxide \(\mathrm{Al}_{2} \mathrm{O}_{3}\) reacts with Sodium hydroxide to form Sodium aluminate. The balanced equation is: \(\mathrm{Al}_{2} \mathrm{O}_{3} + 2 \mathrm{NaOH} \longrightarrow 2 \mathrm{NaAlO}_{2} + \mathrm{H}_{2} \mathrm{O}\)
04

Complete the reaction of \(\mathrm{BeCl}_{2}+\mathrm{C}_{2}\mathrm{H}_{5}\mathrm{OC}_{2}\mathrm{H}_{5}\)

Beryllium chloride \(\mathrm{BeCl}_{2}\) reacts with Diethyl ether \(\mathrm{C}_{2}\mathrm{H}_{5}\mathrm{OC}_{2}\mathrm{H}_{5}\) to form a complex compound. The reaction results in the formation of a coordination complex with the formula \(\mathrm{BeCl}_{2}\cdot \mathrm{(O \ C_{2} H_{5})_{2}}\), the balanced equation is: \(\mathrm{BeCl}_{2} + \mathrm{C}_{2}\mathrm{H}_{5}\mathrm{OC}_{2}\mathrm{H}_{5} \longrightarrow \mathrm{BeCl}_{2}\cdot (\mathrm{O \ C_{2} H_{5})_{2}\)

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