Write balanced chemical equations for the following: (a) Action of conc. nitric acid on sugar (b) Action of zinc with very dilute nitric acid (c) Action of \(\mathrm{PCl}_{5}\) with ethyl alcohol (d) Action of hot conc. \(\mathrm{NaOH}\) with white phosphorus

Short Answer

Expert verified
Balanced reactions are: (a) \(C_{12}H_{22}O_{11} + 14 HNO_3 \rightarrow 11 H_2O + 12 CO_2 + 14 NO_2\), (b) \(Zn + 2 HNO_3 \rightarrow H_2 + Zn(NO_3)_2\), (c) \(C_2H_5OH + PCl_5 \rightarrow C_2H_5Cl + POCl_3 + HCl\), (d) \(3 P_4 + 12 NaOH + 18 H_2O \rightarrow 12 Na_3PO_4 + PH_3\).

Step by step solution

01

Action of conc. nitric acid on sugar

The action of concentrated nitric acid (\(HNO_3\)) on sugar (sucrose) leads to the oxidation of sugar. The equation for this reaction is: \(C_{12}H_{22}O_{11} + 14 HNO_3 \rightarrow 11 H_2O + 12 CO_2 + 14 NO_2\). This equation is already balanced.
02

Action of zinc with very dilute nitric acid

When zinc (\(Zn\)) reacts with very dilute nitric acid (\(HNO_3\)), a displacement reaction occurs where hydrogen gas is evolved. The equation is: \(Zn + 2 HNO_3 \rightarrow H_2 + Zn(NO_3)_2\). This equation is already balanced.
03

Action of PCl5 with ethyl alcohol

Ethyl alcohol (ethanol, \(C_2H_5OH\)) reacts with phosphorus pentachloride (\(PCl_5\)) to produce ethyl chloride and phosphorus oxychloride as per the equation: \(C_2H_5OH + PCl_5 \rightarrow C_2H_5Cl + POCl_3 + HCl\). This equation is already balanced.
04

Action of hot conc. NaOH with white phosphorus

White phosphorus (\(P_4\)) reacts with hot concentrated sodium hydroxide (\(NaOH\)) to form phosphine and sodium orthophosphate. The equation for this reaction is: \(3 P_4 + 12 NaOH + 18 H_2O \rightarrow 12 Na_3PO_4 + PH_3\). This equation is already balanced.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.

Sign-up for free