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Chapter 16: Problem 10

Discuss the action of bleaching powder with the following compounds: (a) \(\mathrm{CO}_{2}\) (b) \(\mathrm{Cl}_{2}\) (c) \(\mathrm{COCl}_{2}\) (d) \(\mathrm{PbO}\) (e) \(\mathrm{H}_{2} \mathrm{SO}_{4}\)

Short Answer

Expert verified
Bleaching powder shows different reactions with different compounds. With CO2, it forms calcium carbonate and chlorine gas. With Cl2, more bleaching powder is produced. With COCl2, it forms calcium oxychloride, carbon dioxide, and chlorine. With PbO, it forms lead(II) chloride, calcium chloride and water. Lastly with H2SO4, it forms calcium sulfate, water, and chlorine gas.

Step by step solution

01

Reacting Bleaching Powder with CO2

Bleaching powder reacts with carbon dioxide to form calcium carbonate and chlorine gas. The reaction can be written as: \( CaOCl2 + CO2 \rightarrow CaCO3 + Cl2 \)
02

Reacting Bleaching Powder with Cl2

When bleaching powder reacts with chlorine gas, it leads to more bleaching powder being produced. The reaction is: \( CaOCl2 + Cl2 \rightarrow CaOCl_{2}Cl_{2} \)
03

Reacting Bleaching Powder with COCl2

Bleaching powder reacts with carbonyl chloride to yield calcium oxychloride, carbon dioxide and chlorine. The reaction is: \( CaOCl2 + COCl2 \rightarrow CaOCl_{2}Cl_{2} + CO2 \)
04

Reacting Bleaching Powder with PbO

Bleaching powder reacts with lead(II) oxide to form lead(II) chloride, calcium chloride and water. The reaction can be expressed as: \( 2CaOCl2 + PbO \rightarrow PbCl2 + 2CaCl2 + H2O \)
05

Reacting Bleaching Powder with H2SO4

Bleaching powder reacts with sulfuric acid to form calcium sulfate, water and chlorine gas. The reaction breakdown is: \( CaOCl2 + H2SO4 \rightarrow CaSO4 + 2H2O + Cl2 \)

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