Discuss the structures of the following compounds. (a) \(\mathrm{IF}_{5}\) (b) \(\mathrm{IO}_{4}^{-}\) (c) \(\mathrm{ClO}_{3}^{-}\) (d) \(\mathrm{Cl}_{2} \mathrm{O}\) (e) \(\mathrm{I}_{2} \mathrm{O}_{5}\) (f) \(\mathrm{IF}_{7}\)

Short Answer

Expert verified
The structures of the compounds are as follows: \(\mathrm{IF}_{5}\) is square pyramidal, \(\mathrm{IO}_{4}^{-}\) is square planar, \(\mathrm{ClO}_{3}^{-}\) is trigonal pyramidal, \(\mathrm{Cl}_{2} \mathrm{O}\) is angular or bent, \(\mathrm{I}_{2} \mathrm{O}_{5}\) is linear, and \(\mathrm{IF}_{7}\) is pentagonal bipyramidal.

Step by step solution

01

Determine the total number of valence electrons and arrange the atoms

In \(\mathrm{IF}_{5}\), the central atom I has 7 valence electrons and each F atom has 7 valence electrons. Since F is more electronegative, it is arranged around I.
02

Draw the Lewis Dot Structure

Join the central atom I with five F atoms by single bonds. Now, place the remaining 2 electrons on the I atom, resulting in a single pair of lone electrons.
03

Determine the shape of the molecule

The shape of \(\mathrm{IF}_{5}\) is square pyramidal which is based on a trigonal bipyramidal arrangement. The same process needs to be followed for \(\mathrm{IO}_{4}^{-}\), \(\mathrm{ClO}_{3}^{-}\), \(\mathrm{Cl}_{2} \mathrm{O}\), \(\mathrm{I}_{2} \mathrm{O}_{5}\), and \(\mathrm{IF}_{7}\).
04

Identify the molecular geometry of remaining compounds

\(\mathrm{IO}_{4}^{-}\) has a molecular geometry of square planar; \(\mathrm{ClO}_{3}^{-}\) is trigonal pyramidal; \(\mathrm{Cl}_{2} \mathrm{O}\) is angular or bent; \(\mathrm{I}_{2} \mathrm{O}_{5}\) is linear, and \(\mathrm{IF}_{7}\) is pentagonal bipyramidal.

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