Discuss the hybridisation and sructure of (a) \(\mathrm{XeF}_{4}\) (b) \(\mathrm{XeO}_{2} \mathrm{~F}_{2}\) (c) \(\mathrm{XeO}_{3}\) (d) \(\mathrm{XeO}_{3} \mathrm{~F}_{2}\)

Short Answer

Expert verified
The hybridization and structure of (a) \(\mathrm{XeF}_{4}\) is \(sp^{3}d^{2}\) and square planar, (b) \(\mathrm{XeO}_{2} \mathrm{~F}_{2}\) is \(sp^{3}d\) and see-saw, (c) \(\mathrm{XeO}_{3}\) is \(sp^{3}\) and pyramidal, and (d) \(\mathrm{XeO}_{3} \mathrm{~F}_{2}\) is \(sp^{3}d^{2}\) and trigonal bipyramidal respectively.

Step by step solution

01

Determine Hybridization of \(\mathrm{XeF}_{4}\)

Count the number of electron pairs around the central atom (Xe), \(\mathrm{XeF}_{4}\) has 4 bond pairs and 2 lone pairs. Therefore, it's hybridisation is \(sp^{3}d^{2}\) and it has a square planar structure.
02

Determine Hybridization of \(\mathrm{XeO}_{2} \mathrm{~F}_{2}\)

Count the number of electron pairs around the central atom (Xe), \(\mathrm{XeO}_{2} \mathrm{~F}_{2}\) has 4 bond pairs and 1 lone pair. Therefore, it's hybridisation is \(sp^{3}d\) and it has a see-saw geometry.
03

Determine Hybridization of \(\mathrm{XeO}_{3}\)

Count the number of electron pairs around the central atom (Xe), \(\mathrm{XeO}_{3}\) has 3 bond pairs and 1 lone pair. Therefore, it's hybridisation is \(sp^{3}\) and it has a pyramidal structure.
04

Determine Hybridization of \(\mathrm{XeO}_{3} \mathrm{~F}_{2}\)

Count the number of electron pairs around the central atom (Xe), \(\mathrm{XeO}_{3} \mathrm{~F}_{2}\) has 5 bond pairs and 0 lone pairs. Therefore, it's hybridisation is \(sp^{3}d^{2}\) and it has a trigonal bipyramidal structure.

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