Discuss the Jahn-Teller effect with the help of an octahedral complex of \(\mathrm{Cu}^{2+}\) ion.

Short Answer

Expert verified
The Jahn-Teller effect in the octahedral complex of \(\mathrm{Cu}^{2+}\) ion is due to its \(d^9\) electronic configuration. The effect induces a distortion in the complex leading to a decrease in the degeneracy of the \(e_g\) orbitals and as a result, a decrease in energy and increase in stability of the complex.

Step by step solution

01

Introduction to the Octahedral Complex of Cu^2+

An octahedral complex is a molecular complex shaped like an octahedron where a central atom is surrounded by six ligands. For \(\mathrm{Cu}^{2+}\), the configuration is \(d^9\) in the octahedral field.
02

Description of the Jahn-Teller Effect

The Jahn-Teller theorem postulates that any non-linear molecule with a spatially degenerate ground-state electron configuration will spontaneously distort to remove that degeneracy. The distortion results in stabilization of the system and is known as the Jahn-Teller effect. In simple terms, it is the distortion of degenerate molecules to lower symmetry to lower energy and achieve greater stability.
03

Application of the Jahn-Teller Effect to the Cu^2+ Octahedral Complex

In a \(\mathrm{Cu}^{2+}\) octahedral complex, the electron configuration is \(d^9\). This configuration is degenerate with two electrons in the \(e_g\) orbital and seven electrons in the \(t_{2g}\) orbital. The \(d^9\) high-spin configuration is not spherical symmetrically and gives rise to Jahn-Teller distortion. The octahedral complex distorts to elongate along one of its molecular axes which leads to a distribution of the \(e_g\) subset into \(e_{g}\) ( \(z^2\) ) and \(e_{g}\) ( \(x^2-y^2\) ) which are different in energy. This leads to the reduction in the degeneracy of the orbitals and stabilization of the complex through the Jahn-Teller effect.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.

Sign-up for free