Explain the following: (a) The ionic radii of \(\mathrm{Ca}^{2+}, \mathrm{Mn}^{2+}\) and \(\mathrm{Zn}^{2+}\) decrease regularly. (b) The ionic radius of \(\mathrm{Ni}^{2+}\) is smaller than that of \(\mathrm{Cu}^{2+}\) in presence of octahedral crystal-field environment of halide ions. (c) \(\mathrm{Co}^{3+}\) preferably adopts octahedral geometry under the effect of strong field ligands. (d) \(\mathrm{Mn}_{2} \mathrm{O}_{4}\) exists in normal spinel structure while \(\mathrm{Fe}_{2} \mathrm{O}_{1}\) exists in inverse spinel structure.

Short Answer

Expert verified
a) The ionic radii of \(\mathrm{Ca}^{2+}\), \(\mathrm{Mn}^{2+}\) decrease due to increased effective nuclear charge moving left to right across a period. b) \(\mathrm{Ni}^{2+}\) has a smaller ionic radius than \(\mathrm{Cu}^{2+}\) in octahedral crystal field due to greater effective nuclear charge. c) \(\mathrm{Co}^{3+}\) prefers octahedral geometry due to the large d-orbital splitting caused by strong field ligands. d) \(\mathrm{Mn}_{2} \mathrm{O}_{4}\) exists in normal spinel structure (divalent ions in octahedral sites), while \(\mathrm{Fe}_{3} \mathrm{O}_{4}\) exists in inverse spinel structure (half of the divalent ions are in tetrahedral sites and the other half along with all of the trivalent ions are in octahedral sites).

Step by step solution

01

Part A: Understanding periodic trends

The ionic radii of \(\mathrm{Ca}^{2+}, \(\mathrm{Mn}^{2+}\) and \(\mathrm{Zn}^{2+}\) decrease regularly because as we move from left to right across a period in the periodic table, the atomic number increases but the extra electrons are added to the same quantum shell. As a result, the increased number of protons pulls the energy levels and thus the electrons closer to the nucleus, leading to decrease in radius.
02

Part B: Applying crystal field theory

In a coordinated environment with octahedral crystal field, the ionic radius of \(\mathrm{Ni}^{2+}\) is smaller than \(\mathrm{Cu}^{2+}\). This is because \(\mathrm{Ni}^{2+}\) has a greater effective nuclear charge, which pulls the electron cloud closer and reduces the ionic radius compared to \(\mathrm{Cu}^{2+}\) which has less effective nuclear charge.
03

Part C: Analyzing ligand field strengths

\(\mathrm{Co}^{3+}\) ion typically prefers an octahedral geometry due to strong field ligands. Strong field ligands lead to a large extent of d-orbital splitting, enabling the \(\mathrm{Co}^{3+}\) ion to achieve a lower energy state by aligning in an octahedral geometry.
04

Part D: Identifying spinel structures

In normal spinel structure like \(\mathrm{Mn}_{2} \mathrm{O}_{4}\), the divalent ion (in this case Mn) occupies the 8 octahedral sites present in the structure. In the inverse spinel structure like \(\mathrm{Fe}_{3} \mathrm{O}_{4}\), however, half of the divalent ions (Fe) are in tetrahedral sites and half are in octahedral sites along with the trivalent ions.

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